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If q and v are positive integers such that q/v= 45.24, how

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If q and v are positive integers such that q/v= 45.24, how [#permalink]

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New post 29 Jul 2006, 00:08
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If q and v are positive integers such that q/v= 45.24, how many two digit numbers COULD be the remainder when q is divided by v?

(A) 12 (B) 13 (C) 14 (D) 15 (E) 16
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Re: PS: Possible Remainders [#permalink]

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New post 29 Jul 2006, 01:02
kevincan wrote:
If q and v are positive integers such that q/v= 45.24, how many two digit numbers COULD be the remainder when q is divided by v?

(A) 12 (B) 13 (C) 14 (D) 15 (E) 16


q = 45.24*v = 45v + 0.24*v

0.24*v = two digit integer
10<= (6/25)*v <100
1.xxx <= (1/25)*v < 16.xxx
the number of multiples of 25 between 1.xx and 16.xx
Thus, 16-2+1=15

D it is!
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 [#permalink]

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New post 29 Jul 2006, 02:13
Nice work! OA and OE

I need to think of more challenging questions. Did you like the one about the obtuse triangles around the clock?
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Re: PS: Possible Remainders [#permalink]

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New post 29 Jul 2006, 07:06
[quote="kevincan"]If q and v are positive integers such that q/v= 45.24, how many two digit numbers COULD be the remainder when q is divided by v?

(A) 12 (B) 13 (C) 14 (D) 15 (E) 16[/quote]
24 Can be expressed as 6/25.So for getting two digit remainder 6/25 has to be multiple of 1,2,3,4...untill the value of 6*n becomes three digit
6*2=12
6*3=18
....
.....
6*16=96(two digit number)

hence total 15 numbers
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 [#permalink]

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New post 29 Jul 2006, 17:30
kevincan wrote:
Nice work! OA and OE

I need to think of more challenging questions. Did you like the one about the obtuse triangles around the clock?


Actually, I haven't tried yet... I'll do it later..
I like your questions :lol: Thanks kevin
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  [#permalink] 29 Jul 2006, 17:30
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