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Re: If q is one root of the equation x^2 + 18x + 11c = 0, where [#permalink]
17 Aug 2014, 09:09
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If q is one root of the equation x^2 + 18x + 11c = 0, where [#permalink]
16 Sep 2014, 12:57
one way to solve it really fast is to factor it: x=-11 thus we get (x+11) in order to get x^2+18x+11c=0, q must be also a negative, otherwise we cannot get to this equation, therefore we get x+q
now we can factor (x+q)(x+11)=0 q+11=18 q*11=11c
since we need q^2-c^2, because every number squared to an even power is a positive number, 11q=11c=>q^2=c^2, and therefore q^2-c^2=0!
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