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If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
 07 Nov 2006, 11:50
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62% (01:35) correct
37% (00:34) wrong based on 34 sessions
If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of the following is the correct ordering of r, s, and t ? A. r < s < t B. r < t < s C. s < t < r D. s < r < t E. t < r < s
Last edited by Bunuel on 11 Apr 2012, 01:40, edited 2 times in total.
Edited the question and added the OA
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girikorat wrote: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of the following is the correct ordering
of r, s, and t ?
A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s
As r,s and t are fractions
s<r<t
Answer is D
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agree D, for simplicity u could just replace the decimal with 1/4
r=1/4
s=r^2=1/8
t=sqrt s=1/2
s<r<t
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Can someone provide a good solution to this? This problem is pretty straightforward, but I'd definitely be confused if it got a lil more complex on the real GMAT... Any help will be greatly appreciated.
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petrifiedbutstanding wrote: Can someone provide a good solution to this? This problem is pretty straightforward, but I'd definitely be confused if it got a lil more complex on the real GMAT... Any help will be greatly appreciated. For, 0<x<1; the higher power of x always be smaller than lower power of x. 0<x<1: x^4<x^3<x^2<x^1<x^{\frac{1}{2}}<x^{\frac{1}{4}}x=1; x^1=x^2=x^3=x^{real numbers}=1x>1; x^{\frac{1}{4}}<x^{\frac{1}{2}}<x^1<x^2<x^3<x^4For x<0; it gets subtle because all even powers become +ve. Try some examples and see what you get. But, there too: consider 0>x>-1; x=-1; -1>x as three separate case.
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
11 Apr 2012, 01:35
I am also in the same boat on this question, can someone give a much better detailed solution to this problem?
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
11 Apr 2012, 01:47
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
26 Jul 2012, 03:58
Hi bunuel, thanks for that example. I had solved it by keeping the fraction itself. Thanks
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
26 Apr 2013, 06:40
Hi Mr Bunuel....
I did solve this question by replacing .04 to .345...........
Can it be wise to tackle it by replacement theory????
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
26 Apr 2013, 08:16
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Simply follow this rule, If x < 1, it reduces in value with each power>1. So for x < 1, x>x^2>x^3>x^4.. and so on In the current example, t=sqrt(0.345) (a value less than 1) r = t^2s = r^2 = t^4So, as per our above rule, t^4<t^2<t implying s<r<t
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of [#permalink]
26 Apr 2013, 23:48
Good way to explain...
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Re: If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which of
[#permalink]
26 Apr 2013, 23:48
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