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# If R = 1 + 2xy + x^2y^2, what is the value of xy? (1) R = 0

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Joined: 25 Jun 2007
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Kudos [?]: 6 [0], given: 0

If R = 1 + 2xy + x^2y^2, what is the value of xy? (1) R = 0 [#permalink]  05 Oct 2007, 23:41
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If R = 1 + 2xy + x^2y^2, what is the value of xy?

(1) R = 0
(2) X > 0
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Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 136 [0], given: 0

R = 1 + 2xy + x^2y^2

R = (xy+1)(xy+1)

statement 1

R=0

0 = (xy+1)(xy+1)

xy+1 = 0

xy = -1

sufficient

statement 2

x > 0

insufficient

the asnwer is (A)

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