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If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the

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Kudos [?]: 18 [0], given: 5

If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the [#permalink]

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New post 18 May 2012, 17:36
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If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the following is equal to the greatest common divisor of r and s?

A. 2 * 5
B. 2^2 * 5
C. 2^3 * 5^2
D. 2*3*5*7
E. 2^3 * 3^2 *5^2 * 7
[Reveal] Spoiler: OA
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Kudos [?]: 455 [0], given: 16

Re: If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the [#permalink]

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New post 18 May 2012, 17:42
GCD = product of prime factors raised to the least power =2^2 x 5

Option B
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Kudos [?]: 73942 [0], given: 9904

Re: If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the [#permalink]

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New post 18 May 2012, 17:45
Expert's post
jsphcal wrote:
If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the following is equal to the greatest common divisor of r and s?

A. 2 * 5
B. 2^2 * 5
C. 2^3 * 5^2
D. 2*3*5*7
E. 2^3 * 3^2 *5^2 * 7


To find the greatest common divisor of two positive integers multiply the common factors of these integers by picking the lowest power of the common factors.

So, the GCD of r=2^3*5^2*7 and s=2^2*3^2*5 is 2^2*5.

Answer: B.
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Re: If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the   [#permalink] 18 May 2012, 17:45
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If r = 2^3 * 5^2 * 7 and s = 2^2 * 3^2 * 5, which of the

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