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If r = 3p+q/2 and s = p тАУ q, for which

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If r = 3p+q/2 and s = p тАУ q, for which [#permalink] New post 14 Nov 2003, 11:31
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A
B
C
D
E

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If r = 3p+q/2 and s = p тАУ q, for which of the following values of p would r2 = s2 ?
(A) 1/5q
(B) 10 тАУ 3/2q
(C) q тАУ 1
(D) 3q
(E) 9/2q тАУ 9
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shubhangi

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 [#permalink] New post 14 Nov 2003, 11:35
What do you mean by r2 and s2?
r * 2 or square(r), same for s?
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 [#permalink] New post 24 Nov 2003, 05:22
A.

I guess you just have to test the answer choices, starting with the choices that are easier to test.

If you substitute p with 1/5q, r^2 will equal s^2.
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 [#permalink] New post 19 Dec 2003, 15:29
if r^2 = s^2 then r= +-s or s = +-r
so (3p+q)/2 = p-q or q-p

you can get p = 3q or p = q/4
I will go with 3q
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 [#permalink] New post 20 Dec 2003, 14:55
The official asnwer is A . I guess ndidi's approach is right.
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 [#permalink] New post 21 Dec 2003, 05:55
I thought r = (3p+q)/2 instead of 3p+q/2
sorry about that. I still could not verify ndidi204's answer. I hope he/she explains it.
  [#permalink] 21 Dec 2003, 05:55
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If r = 3p+q/2 and s = p тАУ q, for which

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