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If r and s are each greater than 0, is (r + n)/(s + n) > [#permalink]
 18 Aug 2009, 22:19
Question Stats:
47% (01:29) correct
52% (00:18) wrong based on 17 sessions
If r and s are each greater than 0, is (r + n)/(s + n) > r/s? (1) n > 0 (2) r < s
Last edited by Bunuel on 13 Dec 2012, 08:05, edited 1 time in total.
OA added.
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Manager
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Answer is A
Anytime we add two positive numbers to a fraction the number gets larger than the original fraction.
Statement 1 says exactly that
Statement 2 is insufficient becasue we need to know that sign of n
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The answer should be A, thanks for explanation
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Answer should be C. must have both conditions. e.g r=3, s=2, n=1
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sher676 wrote: Answer is A
Anytime we add two positive numbers to a fraction the number gets larger than the original fraction.
That's only true if your fraction has a positive numerator and denominator (which we know in this question) *and* if the overall value of the fraction is less than 1. If the value of the fraction is greater than 1, then adding the same positive value to the numerator and denominator will decrease the value of the fraction. For example, if you add 1 to the top and bottom of the fraction 2/3, the value increases to 3/4. If you add 1 to the top and bottom of the fraction 3/2, the value decreases to 4/3.
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Manager
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Should be C.
St 1. if r and s each equal to the same number say 2 it becomes insuff.
st 2. we don't know n's sign
Together Sufficient, hence C
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Re: If r and s are each greater than 0, is (r + n)/(s + n) > [#permalink]
13 Dec 2012, 08:00
Hi Experts i think the answer should be B
but OA as per grockit is C
here is my aproach:-
working on stem
doing cross multiplication we get an equation
rs + ns > rs + nr
simplifying we get
S>R
so our question becomes Is s > r
B gives the solution directly
am i missing something...
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Re: If r and s are each greater than 0, is (r + n)/(s + n) > [#permalink]
13 Dec 2012, 08:11
Archit143 wrote: Hi Experts i think the answer should be B
but OA as per grockit is C
here is my aproach:-
working on stem
doing cross multiplication we get an equation
rs + ns > rs + nr
simplifying we get
S>R
so our question becomes Is s > r
B gives the solution directly
am i missing something... We cannot cross-multiply here since we don;t know the sign of s+n. If r and s are each greater than 0, is (r + n)/(s + n) > r/s?(1) n > 0. Since both n and s are positive, then we can safely cross-multiply and the question becomes: is rs+ns>rs+nr? --> is ns>nr? --> reduce by positive n: is s>r? We don't know that. Not sufficient. (2) r < s. Not sufficient. (1)+(2) the question from (1) became: s>r? The second statement answers it. Sufficient. Answer: C.
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Re: If r and s are each greater than 0, is (r + n)/(s + n) >
[#permalink]
13 Dec 2012, 08:11
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