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RS+R = R(S+1) --> which is ODD Now this implies that R is odd AND S+1 is odd. which means S is even

Ans B.

I am not sure if i got this one ..

i mean if r is odd what is the possibility of s being odd or even ??

If r and s are integers and rs + r is odd, which of the following must be even ?

A. r B. s C. r + s D. rs - r E. r^2 + s

Given that rs + r is odd --> \(rs + r =r*(s+1)=odd\). For the product of two integers, r and s+1, to be odd both must be odd. Theretofore, r and s+1 are odd, which means that r is odd and s is even.

If r and s are integers and rs + r is odd, which of the following must be even ?

If r is factored out to rewrite this as r (s + 1), we can see it as a product of two parts, r and s + 1. For their product to be odd, r must be odd and s + 1 must be odd. We also know that even + odd = odd. For s+1 to be odd, s must be even since 1 is odd. A. R B. s C. r + s D. rs - r E. r^2 + s
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Re: If r and s are integers and rs + r is odd, which of the following must [#permalink]

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29 Jul 2016, 23:56

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