Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

r is a negative integer and is not equal to 1. But it can be any other integer. Therefore insufficient.

Considering statement 2

2r>-5

For this to happen r has to be -2, -1, 0,1,2,...n. Therefore r can be either ODD or EVEN. Insufficient.

Combining the two:Yes. How? from Statement 1-> r is negative and not equal to 1 and from statement 2 we can tell r can only be -2 and therefore negative.

The question is again the same - is my approach correct?

Guys - My sincere apologies to everyone on this forum by asking about the approach. As I said before, GMAT did bite me 3 times previously and this time I am not taking any chances as most of you guys said its always best to work on basics first. Therefore, I want to be sure that my concepts are getting better.

Re: If |r| is not equal to 1, is integer r even? [#permalink]
06 Jul 2011, 07:05

enigma123 wrote:

If |r| is not equal to 1, is integer r even?

1. r is not positive 2. 2r>-5

This is my approach:

Considering statement 1

r is a negative integer and is not equal to 1. But it can be any other integer. Therefore insufficient.

Considering statement 2

2r>-5

For this to happen r has to be -2, -1, 0,1,2,...n. Therefore r can be either ODD or EVEN. Insufficient.

Combining the two:Yes. How? from Statement 1-> r is negative and not equal to 1 and from statement 2 we can tell r can only be -2 and therefore negative.

The question is again the same - is my approach correct?

Guys - My sincere apologies to everyone on this forum by asking about the approach. As I said before, GMAT did bite me 3 times previously and this time I am not taking any chances as most of you guys said its always best to work on basics first. Therefore, I want to be sure that my concepts are getting better.

Re: If |r| is not equal to 1, is integer r even? [#permalink]
03 Aug 2011, 20:26

enigma123,

Your approach to solve this problem is correct. The only correction needed is that when you combine both statements, you take the possible value of r to be only -2, but the value of r can also be 0 (as zero is a non-negative integer. As an aside, it is also non-positive).

Some points to remember: (1) Negative integers too can be even (2) 0 is the only integer that is both non-negative as well as non-positive. If ever you come across a question that asks you to work with non-negative integers, don't just take positive integers as the valid set. Remember to include the zero. Similarly, non-positive integers also include zero _________________

Re: If |r| is not equal to 1, is integer r even? [#permalink]
08 Oct 2015, 00:54

enigma123 wrote:

If |r| is not equal to 1, is integer r even?

1. r is not positive 2. 2r>-5

This is my approach:

Considering statement 1

r is a negative integer and is not equal to 1. But it can be any other integer. Therefore insufficient.

Considering statement 2

2r>-5

For this to happen r has to be -2, -1, 0,1,2,...n. Therefore r can be either ODD or EVEN. Insufficient.

Combining the two:Yes. How? from Statement 1-> r is negative and not equal to 1 and from statement 2 we can tell r can only be -2 and therefore negative.

The question is again the same - is my approach correct?

Guys - My sincere apologies to everyone on this forum by asking about the approach. As I said before, GMAT did bite me 3 times previously and this time I am not taking any chances as most of you guys said its always best to work on basics first. Therefore, I want to be sure that my concepts are getting better.

Re: If |r| is not equal to 1, is integer r even? [#permalink]
08 Oct 2015, 04:59

jimwild wrote:

enigma123 wrote:

If |r| is not equal to 1, is integer r even?

1. r is not positive 2. 2r>-5

This is my approach:

Considering statement 1

r is a negative integer and is not equal to 1. But it can be any other integer. Therefore insufficient.

Considering statement 2

2r>-5

For this to happen r has to be -2, -1, 0,1,2,...n. Therefore r can be either ODD or EVEN. Insufficient.

Combining the two:Yes. How? from Statement 1-> r is negative and not equal to 1 and from statement 2 we can tell r can only be -2 and therefore negative.

The question is again the same - is my approach correct?

Guys - My sincere apologies to everyone on this forum by asking about the approach. As I said before, GMAT did bite me 3 times previously and this time I am not taking any chances as most of you guys said its always best to work on basics first. Therefore, I want to be sure that my concepts are getting better.

Where it is mentionned r is an integer ?

last part of the question stem. If |r| is not equal to 1, is integer r even? Kind of tricky because most of the time it will state that it is an integer near the beginning.

r is a negative integer and is not equal to 1. But it can be any other integer. Therefore insufficient.

Considering statement 2

2r>-5

For this to happen r has to be -2, -1, 0,1,2,...n. Therefore r can be either ODD or EVEN. Insufficient.

Combining the two:Yes. How? from Statement 1-> r is negative and not equal to 1 and from statement 2 we can tell r can only be -2 and therefore negative.

The question is again the same - is my approach correct?

Guys - My sincere apologies to everyone on this forum by asking about the approach. As I said before, GMAT did bite me 3 times previously and this time I am not taking any chances as most of you guys said its always best to work on basics first. Therefore, I want to be sure that my concepts are getting better.

If |r| is not equal to 1, is integer r even?

\(|r|\neq{1}\) --> \(r\neq{1}\) and \(r\neq{-1}\).

(1) \(r\) is not positive --> Clearly insufficient, \(r\) can be any non-positive integer (except -1) even or odd (0, -2, -3, -4, ...).

(2) \(2r>-5\) --> \(r>-\frac{5}{2}=-2.5\) --> again \(r\) can be even or odd (except -1 and 1): -2, 0, 2, 3, 4, 5, ... Not sufficient.

(1)+(2) \(r\) is not positive and \(r>-2.5\) --> \(r\) can be -2, -1, or 0. But as given that \(r\neq{-1}\) then only valid solutions for \(r\) are -2 and 0, both are even. Sufficient.

Low GPA MBA Acceptance Rate Analysis Many applicants worry about applying to business school if they have a low GPA. I analyzed the low GPA MBA acceptance rate at...

In out-of-the-way places of the heart, Where your thoughts never think to wander, This beginning has been quietly forming, Waiting until you were ready to emerge. For a long...