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If r + s > 2t, is r > t ? (1) t > s (2) r > s

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If r + s > 2t, is r > t ? (1) t > s (2) r > s [#permalink]

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09 Jul 2007, 19:05
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If r + s > 2t, is r > t ?

(1) t > s

(2) r > s
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Joined: 07 Feb 2007
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09 Jul 2007, 19:14
dreamgmat1 wrote:
If r + s > 2t, is r > t ?

(1) t > s

(2) r > s

(1) r+s>2t --> r>2t-s=t+t-s>t Sufficient;
(2) r+s>2t --> 2r>r+s>2t --> r>t Sufficient

Last edited by wudy on 09 Jul 2007, 19:15, edited 1 time in total.
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09 Jul 2007, 19:14
St1:
E.g.
t = 5, s = 3, then 2t = 10. So r+s > 10 --> r > 7 (r could be >t or <t> 2t and r > t. But it could also be
r = 8, s = 3, t = 10 then r+s > 2t and r > t. r could be >t or <t> 2t and r > t. But it could also be
r = 8, s = 3, t = 10 then r+s > 2t and r > t. r could be >t or <t. insufficient.

Ans E
09 Jul 2007, 19:14
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