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If r + s > 2t, is r > t ? (1) t > s (2) r > s Is

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If r + s > 2t, is r > t ? (1) t > s (2) r > s Is [#permalink] New post 20 May 2009, 14:43
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If r + s > 2t, is r > t ?

(1) t > s

(2) r > s

Is there a simple method of solving such problems?
1 KUDOS received
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Location: Toronto
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Kudos [?]: 705 [1] , given: 3

Re: Numbers- MGMAT [#permalink] New post 21 May 2009, 05:58
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gmatprep09 wrote:
If r + s > 2t, is r > t ?

(1) t > s

(2) r > s

Is there a simple method of solving such problems?


Using S1: If t > s, then r + t > r + s, and using the information in the question, r + t > 2t, or r > t.

Using S2: If r > s, then r + r > r + s, and using the information in the question, 2r > 2t, or r > t.

D.

Alternatively you might see that the question is really about averages. We can rewrite the information in the question as (r+s)/2 > t. That is, we know that the average of r and s is greater than t. Now, we're just averaging two letters here, r and s. If they're different, one of them must be 'above average' (and therefore greater than t), and one must be 'below average' (and then possibly less than t, possibly not). Statement 1 tells us that s must be below average, so r must be above average; sufficient. Statement 2 tells us that s is smaller than r, so sufficient. D.
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Joined: 11 Apr 2009
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Re: Numbers- MGMAT [#permalink] New post 21 May 2009, 07:08
That was a great explanation at the end there IanStewart. Appreciate it.
Re: Numbers- MGMAT   [#permalink] 21 May 2009, 07:08
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