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If r, s, and t are all positive integers, what is the

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If r, s, and t are all positive integers, what is the [#permalink] New post 02 Aug 2012, 15:00
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If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

(1) s is even
(2) rs = 4
[Reveal] Spoiler: OA

Last edited by Bunuel on 02 Aug 2012, 15:10, edited 1 time in total.
Moved to DS subforum, edited the question and renamed the topic.
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 02 Aug 2012, 15:19
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If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

First of all, when a positive integer is divided by 10, the remainder is the units digit of that integer. For example, 30 divided by 10 yields the remainder of 0, 31 divided by 10 yields the remainder of 1, 32 divided by 10 yields the remainder of 2, ...

Next, the units digit of 2 in positive integer power repeats in blocks of 4: {2, 4, 8, 6}

The units digit of 2^1 is 2;
The units digit of 2^2 is 4;
The units digit of 2^3 is 8;
The units digit of 2^4 is 6;
The units digit of 2^5 is 2, AGAIN;
...

(1) s is even --> rst is even, hence the units digit of 2^(rst) is either 4 or 6. Not sufficient.

(2) rs = 4 --> rst is a multiple of 4, hence the units digit of 2^(rst) is the same as the units digit of 2^4 so 6, which means that the remainder upon division of 2^(rst) by 10 is 6. Sufficient.

Answer: B.

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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 11 Aug 2013, 04:39
r,s,t are +ve

REM(2^rst/10) ?

(1).

s is even also even * even = even and even*odd=even

But REM(2^2/10) and REM(2^4/10) are different hence insufficient .

(2).

rs=4

REM(2^4t/10)

REM(2^4/10) ....REM(2^8/10).......REM(2^12/10) .... All are same

Hence sufficient

(B). it is !
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Re: If r, s, and t are all positive integers, what is the remain [#permalink] New post 19 Aug 2013, 05:42
a) if s is even, i.e. rst = even -> 2^even/10 -> can't determine
b) rs = 4, i.e. rst = 4t -> 2^4t/10 -> 2^4t will always have 6 in unit's place(always the multiplication for unit place will be 6*6), so remainder will be 6 -> determined.

Hence, B is the answer.
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Re: If r, s, and t are all positive integers, what is the remain [#permalink] New post 19 Aug 2013, 05:43
Stiv wrote:
If r, s, and t are all positive integers, what is the remainder when 2^{rst} is divided by 10?



(1) s is even

(2) rs = 4


since we are dividing by 10 means remainder will depend on only the unit digit of 2^{rst}

moreover we know unit digit of2^{4n} = 6
unit digit of 2^{4n+1} = 2
unit digit of 2^{4n+2} = 4
unit digit of 2^{4n+3} = 8

so determining the unit digit we should be able to make 2^{rst} in any of the above form.

(1) s is even
not clear it can be of form 2^{4n} or 2^{4n+2}
hence not sufficient.

2)rs = 4
clearly we will get 2^{4s}==>hence unit digit will be6
hence remainder will be 6.
hence sufficient.

hence B
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 09 Mar 2014, 12:22
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 09 Mar 2014, 15:40
Any integer that does not end in 0 will have a positive remainder when divided by 10. Specifically, the remainder will be equal to the ones column. No power of 2 ends in 0. We need the units digit of 2^(rst).

2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64

Every fourth power of 2 repeats.

Statement 1 tells us the units digit will be 4 or 6. Not sufficient.

Statement 2 is sufficient. rst will be a multiple of 4, with units digit 6. Sufficient.

The answer is B.
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 12 Jun 2014, 19:11
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 13 Jun 2014, 00:37
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snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5} not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 13 Jun 2014, 02:19
Bunuel wrote:
snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5} not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.



Thanks Bunuel for your reply. I understood that one should not cancel out however cant understand 2^4t/10 is simplified into 2^4t-1/5 and not 2^3t/5. Don't we cancel the powers. for Example 2^3/2= 2^2. then why cant it be in the previous one.Please help.Thanks
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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 13 Jun 2014, 02:27
Expert's post
snehamd1309 wrote:
Bunuel wrote:
snehamd1309 wrote:
If r, s, and t are all positive integers, what is the remainder of 2^p/10, if p = rst?

(1) s is even

(2) p = 4t

Hi everyone, i have a doubt with statement B. since p=4t so when divided by 10 we can cancel a 2 from both numerator and denominator so we have 2^3t/5 which is 8^t/5 so in this case we have different remainders each time.

Please advice.


\frac{2^{4t}}{10}=\frac{2^{4t-1}}{5} not 2^3t/5. Also, when we are asked to find the remainder of a/b it's not correct to reduce the fraction and find the remainder of the resulting fraction. For example, the remainder when 15 is divided by 6 is 3, but if you reduce that by 3 and find the remainder of 5 by 2 you'd get the remainder of 1.

Hope its clear.



Thanks Bunuel for your reply. I understood that one should not cancel out however cant understand 2^4t/10 is simplified into 2^4t-1/5 and not 2^3t/5. Don't we cancel the powers. for Example 2^3/2= 2^2. then why cant it be in the previous one.Please help.Thanks


\frac{a^n}{a^m}=a^{n-m}. Hence, \frac{2^3}{2^2}=2^{3-2}=2 the same way: \frac{2^{4t}}{2}=2^{4t-1}.

Theory on Exponents: math-number-theory-88376.html

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Re: If r, s, and t are all positive integers, what is the [#permalink] New post 13 Jun 2014, 03:13
jcmorales2012 wrote:
If r, s, and t are all positive integers, what is the remainder when 2^(rst) is divided by 10?

(1) s is even
(2) rs = 4


Remainder when divided by 10 = last digit

Last digit of 2 ^4 = 2^8 = 2^16 and so on.....

Statement I in insufficient:

If rst = 2 then 2 ^2 = 4 and rst =4 then 2 ^4 = last digit is 6

Statement II is sufficient:

If rs = 4 then rst is a multiple of 4 which means rst = 4k hence 2^4, 2^8, 2^12 will give the same last digit.

Hence the answer is B.
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Re: If r, s, and t are all positive integers, what is the   [#permalink] 13 Jun 2014, 03:13
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