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If s and t are two different #s on the number line, is s + t

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If s and t are two different #s on the number line, is s + t [#permalink] New post 25 Mar 2007, 11:10
00:00
A
B
C
D
E

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If s and t are two different #s on the number line, is s + t = 0 ?

A) distance between s and 0 is the same as distance between s and t
B) 0 is between s and t

The answer is A, but why not D ?
I know I am missing something very trivial here .. can one of you help me with this ? :)
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 [#permalink] New post 25 Mar 2007, 11:15
a correction in statement A -

distance between s and 0 is the same as distance between t and 0 !!
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 [#permalink] New post 25 Mar 2007, 11:22
It seems to me that B is merely a rephrased statement of A
So, i don't see why not D

Where did you get this question from ?!
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 [#permalink] New post 25 Mar 2007, 11:48
Edit: It is A, because it says they are DIFFERENT numbers on the numberline.

The only way their distance from the 0 can be the same is if they are the same numbers, or if they are opposites. Since it tells us they are different numbers, s=-t, and therefore s+ t=0
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 [#permalink] New post 25 Mar 2007, 12:46
hi , the above question is from gmat prep !

well since they are different numbers, and 0 is between s and t, should'nt
s + t =0 ?
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 [#permalink] New post 25 Mar 2007, 12:56
grad_mba wrote:
hi , the above question is from gmat prep !

well since they are different numbers, and 0 is between s and t, should'nt
s + t =0 ?


well not necessarily

If S=-10000
and t=1

they are both different numbers, and between 0. However their sum doesn't equal zero.

So it could be, but it also couldn't be. So that statement alone is insufficient.
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 [#permalink] New post 25 Mar 2007, 12:57
0 is betn doesn't mean 0 is the midpoint but just that it separates s and t in oppo. directions on the number line
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 [#permalink] New post 25 Mar 2007, 13:37
ahhhh !! jeez .. i hate it when they test verbal skills in quants !!
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 [#permalink] New post 25 Mar 2007, 15:50
grad_mba wrote:
a correction in statement A -

distance between s and 0 is the same as distance between t and 0 !!


before the correction the answer is (E). neither the statement is sufficient.

after it the question has became very simple. without doubt it's (A).
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 [#permalink] New post 25 Mar 2007, 21:07
aaaaaaaaaaah

Between is different from Midpoint

they got me.
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 [#permalink] New post 27 Mar 2007, 17:24
Trick - 'DIFFERENT' integer.

There is only one case where the s and t are equidistant from 0. That means one of them is positive and another one is negative. This satisfies s+t = 0
  [#permalink] 27 Mar 2007, 17:24
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