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# If s is a two-digit number (so s = qp with q and p digits),

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If s is a two-digit number (so s = qp with q and p digits), [#permalink]  26 Jan 2004, 19:04
If s is a two-digit number (so s = qp with q and p digits), what is the last digit p of s?

(1) The number 3s is a three-digit number whose last digit is p
(2) The digit p is less than 7
Intern
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[#permalink]  26 Jan 2004, 19:17
(1) 3p=p....=> p=5
(2) insufficient...

So answer is (A).
SVP
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[#permalink]  26 Jan 2004, 19:20
Thats what I opted for.....but the official answer is E. shubhangi can you explain why E?
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[#permalink]  26 Jan 2004, 19:39
E as 3 multiplied by _5 gives 5 as last digit and the number can be 35 , 35 ,55, 65, 75, 85,95
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[#permalink]  26 Jan 2004, 19:42
Explanation:

1*3=3
2*3=6
3*3=9
4*3=2
5*3=5 (3p=p)
6*3=8
7*3=1
8*3=4
9*3=7

but we forgot 0

0*3=0

so we cannot conclude whether is 0 or 5....(E)

Last edited by Zeka on 27 Jan 2004, 04:46, edited 1 time in total.
Senior Manager
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[#permalink]  26 Jan 2004, 19:43
It states in 1st state.. 3s ...means 3qp.. we cant get any info from this statement.
neither with 2nd state.. it just says that it is less than 7.. it can be 1-7..any number

I dont know.. from where did u get 5 and multiple..rakesh
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shubhangi

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[#permalink]  26 Jan 2004, 19:46
rakesh1239 wrote:
E as 3 multiplied by _5 gives 5 as last digit and the number can be 35 , 35 ,55, 65, 75, 85,95

The right answer, but the wrong explanation...the question was: what is the last digit p of s?....

(1) 0 and 5
(2) doesn't eliminate one of those two possible solutions...

So ..E
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[#permalink]  28 Jan 2004, 23:05
Why are you guys only conseding the digit 5. Why not 0. 0 and 5 are the digits which will be same it multiplied by 3, but then as Subhangi said there will be a lot of numbers 40,50.....,45,55,65 etc.
E   [#permalink] 28 Jan 2004, 23:05
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# If s is a two-digit number (so s = qp with q and p digits),

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