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If s is the sum of consecutive even integers w, x, y, and z

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If s is the sum of consecutive even integers w, x, y, and z [#permalink] New post 05 Jun 2012, 18:10
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Question Stats:

72% (02:24) correct 28% (01:38) wrong based on 47 sessions
If s is the sum of consecutive even integers w, x, y, and z, where w < x < y < z, all of the following must be true EXCEPT

A. z - w = 3(y - x)
B. s is divisible by 8
C. The average of w, x, y, and z is odd
D. s is divisible by 4
E. w + x + 8 = y + z
[Reveal] Spoiler: OA

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Re: ps [#permalink] New post 06 Jun 2012, 00:15
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alchemist009 wrote:
If s is the sum of consecutive even integers w, x, y, and z,
where w < x < y < z, all of the following must be true
EXCEPT
(A) z - w = 3(y - x)
(B) s is divisible by 8
(C) The average of w, x, y, and z is odd
(D) s is divisible by 4
(E) w + x + 8 = y + z


Just assume that the numbers are 2a, 2a+2, 2a+4 and 2a+6.

s = 2a + 2a+2 + 2a+4 + 2a+6 = 8a + 12

Focus on the easiest options first. You see that s is not divisible by 8. Answer (B)

Or you can take values: w = 0, x = 2, y = 4, z = 6. Their sum is 12 = s.
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Re: ps   [#permalink] 06 Jun 2012, 00:15
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If s is the sum of consecutive even integers w, x, y, and z

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