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If s, u, and v are positive integers, and 2^s = 2^u + 2^v,

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If s, u, and v are positive integers, and 2^s = 2^u + 2^v, [#permalink] New post 19 Mar 2006, 16:26
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If s, u, and v are positive integers, and 2^s = 2^u + 2^v, which of the following must be true:

1: s=u
2: u does not equal v
3: s > v

A) None
B) I only
C) II only
D) III only
E) II and III only

Please explain your answers.
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Re: PS Exponents [#permalink] New post 19 Mar 2006, 16:37
[quote="jcgoodchild"]If s, u, and v are positive integers, and 2^s = 2^u + 2^v, which of the following must be true:

i. s=u....... not possible cuz even if v is o or -ve, s must be > u.



ii. u does not equal v ............ not true. if s = 3, u=v=2. so not true.



iii. s > v. it is a must cuz even if either u or v is -ve, s must be > v.

so D is correct.
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Re: PS Exponents [#permalink] New post 19 Mar 2006, 16:40
jcgoodchild wrote:
If s, u, and v are positive integers, and 2^s = 2^u + 2^v, which of the following must be true:

1: s=u
2: u does not equal v
3: s > v

A) None
B) I only
C) II only
D) III only
E) II and III only

Please explain your answers.


for 1:
s,u,v > 0
therefore v > = 1 thus
s cannot be equal to u

for 2:
is actually the opposite for s,u,v > 0 and integers u does always equal v


for 3:

s,u,v > 0

from 2 we know that U=V then s>v

so I would say D
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 [#permalink] New post 19 Mar 2006, 21:50
1) Not true.
If s = u, then v must be 0 which cannot be the case since v must be a positive integer.

2) Not true.
u and v can be equal. If s = 3, u and v = 2

3) True
If s, u and v are positive integers, then s must always be greater than v.

I go with D
  [#permalink] 19 Mar 2006, 21:50
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If s, u, and v are positive integers, and 2^s = 2^u + 2^v,

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