Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

St. (1) insufficient as we should not forget "0", which is neither positive nor negative. sets can be

{-1, -1, 0, 2}, the mean is -.5, which is negative, or {-1,0,2,4} the mean is 1 which is positive.

St. (2) is also, insufficient, since the set can look like {-1, 0}, the median is the middle number between -1 and 0, which is -.5, so negative, ot it can be {-1,0, 4,4} with median 2, which is positive

putting statements (1) and (2) together does not provide any additional information that can be considered, so Ans. is E.

Not so.

If set S consists of even number of integers, is the median of set S negative?

Set consists of even number of integers --> median=sum of two middle integers/2

(1) Exactly half of all elements of set S are positive --> either all other are negative or all but one, which at this case must be 0. Not sufficient.

(2) The largest negative element of set S is -1 --> not sufficient

(1)+(2) half positive, biggest negative -1 --> median is either (0 + positive)/2=positive (so not negative) or (-1 + at least smallest positive integer, which is 1)/2=0 (min value of median in this case) also not negative. Q was is the median negative answer NO. SUFFICIENT

Just got hit by a lightening and clearly see why OA is C:

Stem: the set has even number of integers.
stmt 1: half of them are positive
stmt2: -1 is the largest negative.

taking stmt 1 & 2 there can be only two numbers in the set since largest negative is -1 & numbers in the set is even & half of all no in the set is positivr. If zero is not a positive integers, the other integer has to be 1 or greater than 1.

Possible set:
-1,1
-1, 1+

Therefore median, under such circumstances, will always be non-negative.

Last edited by mirhaque on 21 Feb 2005, 07:01, edited 1 time in total.

Re: Median negative?? [#permalink]
04 Aug 2009, 00:31

1

This post received KUDOS

arvs212 wrote:

If set S consists of even number of integers, is the median of set S negative?

1)Exactly half of all elements of set S are positive. 2)The largest negative element of set S is -1.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

plzzz give answers with explanations...thnx

IMO C should be the answer.. take statement 1, it means that half are positive and other half may include all negative numbers or negative numbers and a zero.. not suff.. take 2.. from this we cannot say anything about the median.. all nos. can be negative or some may be negative.. we don't know.. insuff. take both: half are positive.. other half would be negative. the largest negative is -1 and all are integers.. so minimum positive would be 1. so median will be (-1 + 1)/2 = 0.. hence median is not negative.. median in this case could me 0 or more than 0 but will never be negative.. hence suff.. thus C..

Re: If set S consists of even number of integers, is the median [#permalink]
02 Mar 2013, 11:36

1

This post received KUDOS

I am confused with the second statement:- The largest negative element in the set is -1. Shouldn't it be smallest negative integer?

When the largest negative integer is mentioned, does is it not mean that the set can't have a larger (than -1) integer, but have a smaller(-2,-100 etc) negative integer?

Just got hit by a lightening and clearly see why OA is C:

Stem: the set has even number of integers. stmt 1: half of them are positive stmt2: -1 is the largest negative.

taking stmt 1 & 2 there can be only two numbers in the set since largest negative is -1 & numbers in the set is even & half of all no in the set is positivr. If zero is not a positive integers, the other integer has to be 1 or greater than 1.

Possible set: -1,1 -1, 1+

Therefore median, under such circumstances, will always be non-negative.

But you guys are ignoring one case:-

set ={ 12, 3, 1, -1, -5, -7}
Here the median is 0, which is niether +ve nor -ve.
So I think it shud be E.

Just got hit by a lightening and clearly see why OA is C:

Stem: the set has even number of integers. stmt 1: half of them are positive stmt2: -1 is the largest negative.

taking stmt 1 & 2 there can be only two numbers in the set since largest negative is -1 & numbers in the set is even & half of all no in the set is positivr. If zero is not a positive integers, the other integer has to be 1 or greater than 1.

Possible set: -1,1 -1, 1+

Therefore median, under such circumstances, will always be non-negative.

But you guys are ignoring one case:-

set ={ 12, 3, 1, -1, -5, -7} Here the median is 0, which is niether +ve nor -ve. So I think it shud be E.

read 1) it says that half of all integers are positive => there is only one pos integers because there is only one neg integer

Just got hit by a lightening and clearly see why OA is C:

Stem: the set has even number of integers. stmt 1: half of them are positive stmt2: -1 is the largest negative.

taking stmt 1 & 2 there can be only two numbers in the set since largest negative is -1 & numbers in the set is even & half of all no in the set is positivr. If zero is not a positive integers, the other integer has to be 1 or greater than 1.

Possible set: -1,1 -1, 1+

Therefore median, under such circumstances, will always be non-negative.

But you guys are ignoring one case:-

set ={ 12, 3, 1, -1, -5, -7} Here the median is 0, which is niether +ve nor -ve. So I think it shud be E.

Vijo, the question is to know if the median is negative...we knowthat the median is at least equal to 0 so we can answer to the question : no, it is impossible that the median is negative. Median is O or any positive number so C is ok to answer NO to the question

Re: Median negative?? [#permalink]
04 Aug 2009, 00:35

arvs212 wrote:

If set S consists of even number of integers, is the median of set S negative?

1)Exactly half of all elements of set S are positive. 2)The largest negative element of set S is -1.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

plzzz give answers with explanations...thnx

IMO E,

1. Is Insuff, as it doesn't tell anything about -ve no. ( I mean the range or values) 2. Is also insuff.

Lets combine 1 & 2. Lets consider an example here. S = ( -3, -2, -1, 1, 2, 3) ( as we know from st 2. that Largest -ve no. is -1 ) In this case the median is 0 and now consider S= ( -3, -2, -1, 2, 3, 4) In this case Median is 1/2 and when S= ( -3, -2, -1, 0, 3, 4) Median = -1/2 Hence 1 & 2 combined also is insuff.

Re: Median negative?? [#permalink]
04 Aug 2009, 00:50

arvs212 wrote:

If set S consists of even number of integers, is the median of set S negative?

1)Exactly half of all elements of set S are positive. 2)The largest negative element of set S is -1.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

plzzz give answers with explanations...thnx

I think its C

1) Does not solve it. Good but not insufficient. 2) The next number is not 0 but a +ve one so you can say S is not a negative.

I hope. (Sorry if i am not right, I am new here just joined gmatclub)

Re: Median negative?? [#permalink]
05 Aug 2009, 04:34

nitishmahajan wrote:

arvs212 wrote:

If set S consists of even number of integers, is the median of set S negative?

1)Exactly half of all elements of set S are positive. 2)The largest negative element of set S is -1.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

plzzz give answers with explanations...thnx

IMO E,

1. Is Insuff, as it doesn't tell anything about -ve no. ( I mean the range or values) 2. Is also insuff.

Lets combine 1 & 2. Lets consider an example here. S = ( -3, -2, -1, 1, 2, 3) ( as we know from st 2. that Largest -ve no. is -1 ) In this case the median is 0 and now consider S= ( -3, -2, -1, 2, 3, 4) In this case Median is 1/2 and when S= ( -3, -2, -1, 0, 3, 4) Median = -1/2 Hence 1 & 2 combined also is insuff.

Please post OA also.

and when S= ( -3, -2, -1, 0, 3, 4) Median = -1/2---------- this case will not arse when we are comibining stmnt 1 &2 cos, one says half of the numbers are positive. so we can not have the "0" there.

Re: Median negative?? [#permalink]
05 Aug 2009, 05:16

definition of median: In probability theory and statistics, a median is described as the number separating the higher half of a sample, a population, or a probability distribution, from the lower half. The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one. If there is an even number of observations, the median is not unique, so one often takes the mean of the two middle values.

so in this case, we can have a set of -3 -2 -1 1 2 3, hence going by the rule stated above, the median of the set is (-1+1)/2 = 0, and 0 is neither positive nor negative, how is this one C?

Re: Median negative?? [#permalink]
05 Aug 2009, 05:39

sprtng wrote:

definition of median: In probability theory and statistics, a median is described as the number separating the higher half of a sample, a population, or a probability distribution, from the lower half. The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one. If there is an even number of observations, the median is not unique, so one often takes the mean of the two middle values.

so in this case, we can have a set of -3 -2 -1 1 2 3, hence going by the rule stated above, the median of the set is (-1+1)/2 = 0, and 0 is neither positive nor negative, how is this one C?

combining 1&2 we can get the median is either 0 or positive. for any of these case, median is non negative. hence we can answer.

Guys,I am not understanding why you people are saying that the set consists of only 2 elements..the answer stands at C only: eg.: {-2, -1 ,1 ,2} median=0. Is the median -ive?NO (o is neither positive nor negative)

I thought it was B initially until you read the statement more carefully.

It says it consist of even number of intergers. So the set can have either 2,4,6,8 numbers.

1) insuff 2) insuff

1) + 2) = -1 is the highest negative value. So the next highest value thats positive is 1. In that case the median is 0. So no the median is not negative.

If you work with any number higher than 1, the median is positive. Therefore the median of set S is not negative.