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1)
We have six numbers and a median of 19, thus the median has to be between 18 and x or y, which is egally.

The stem tells us that the median is 19 so either x or y has to be 20.

We know nothing about the other value, therefore can't determine the range

2) The average is 20, but we can't decide what the biggest number is, because we don't know the smallest; x or y could be smaller than 11

1+2) Either x or y is 20, see statement 1

The other value has to be greater than 18 and greater than 28 (since the smallest number 11 and the greatest number 28 don't support an average of 20)
The remaining value has to be 29

A very good real world illustration of mean and median [#permalink]
21 Jan 2006, 08:37

Ten people are riding on a bus in Redmond, Washington. The mean income of those riders is $50,000 a year. The median income of those riders is also $50,000 a year.

Joe Blow gets off the bus. Bill Gates gets on.

The median income of those riders remains $50,000 a year. But the mean income is now somewhere in the neighborhood of $50 million or so. A source now could say that the average income of those bus riders is 50 million bucks. But those other nine riders didn't become millionaires just because Bill Gates got on their bus. A reporter who writes that the "average rider" on that bus earns $50,000 a year, using the median, provides a far more accurate picture of those bus riders' place in the economy.

Good job people, the OA is "C". GMATT73, its interesting to note your approach, I am just wondering if it will work all the time! The remaining explanations are more of less the standard way of solving it; prash_c - nice story to explain a concept