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1 st statement)
x can be 4 since it is divisible by 4,2,1
x can be 9 since it is divisible by 9,3,1
so insuff
2 st)
x can be 9 9,3,1
and 25 5 25 1
and 49 49 7 1
I am not sure but E _________________

1 st statement) x can be 4 since it is divisible by 4,2,1 x can be 9 since it is divisible by 9,3,1 so insuff 2 st) x can be 9 9,3,1 and 25 5 25 1 and 49 49 7 1 I am not sure but E

You may not know it but if x=4 - sqrt(4) = 2 - prime number
same with x=9

1. x is divisible by exactly three positive integers

any integer is divisable by itself and 1. This gives us 2 positive integers.

If there is only one third integer that divides x - it must be a prime number, because otherwise factors of that third integer would also divide x.

So x is divisable by 1, x and some prime.
That means x = (some prime)^n
But if n>2 x must be divisable by (some prime)^(n-1) - contradiction.
So far we found out, that x = (some prime)^2 => sqrt(x) = some prime

Sufficient

2. all positive factors of x are odd

pick x = 5*5*3*3 => sqrt(x) = 5*3 - not a prime number

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