Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 19 May 2013, 20:14
Customize  |  Hide

Search
Register
New posts
Unanswered

If square roots of numbers are positive.. Is a<c?

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Manager
Manager
User avatar
Joined: 23 Aug 2011
Posts: 83
Followers: 3

Kudos [?]: 19 [0], given: 13

If square roots of numbers are positive.. Is a<c? [#permalink] New post 27 Aug 2012, 11:41
00:00

Question Stats:

50% (02:36) correct 50% (01:31) wrong based on 1 sessions
If square roots of numbers are considered positive and \sqrt{a} + \sqrt{b} = \sqrt{c} + \sqrt{d} + \sqrt{e}, then is a < c?

1.) c = d

2.)\sqrt{b}+\sqrt{d}<\sqrt{e}
[Reveal] Spoiler: OA

_________________

Whatever one does in life is a repetition of what one has done several times in one's life!
If my post was worth it, then i deserve kudos :)

Director
Director
User avatar
Joined: 22 Mar 2011
Posts: 608
WE: Science (Education)
Followers: 43

Kudos [?]: 267 [0], given: 43

GMAT Tests User
Re: If square roots of numbers are positive.. Is a<c? [#permalink] New post 27 Aug 2012, 14:39
conty911 wrote:
If square roots of numbers are considered positive and \sqrt{a} + \sqrt{b} = \sqrt{c} + \sqrt{d} + \sqrt{e}, then is a < c?

1.) c = d

2.)\sqrt{b}+\sqrt{d}<\sqrt{e}


Since all the numbers are positive and the square roots are also positive, the question can be restated as is \sqrt{a}<\sqrt{c}?
Also, (1) can be replaced by \sqrt{c}=\sqrt{d}.

(1) Obviously not sufficient. Too many degrees of freedom to choose values for the five variables.

(2) Since \sqrt{b}+\sqrt{d}<\sqrt{e} necessarily \sqrt{b}<\sqrt{e} and then, using the equality in the question stem, we can deduce that \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c}. In conclusion, \sqrt{a}>\sqrt{c}.
Sufficient.

Answer B
_________________

PhD in Applied Mathematics
Love GMAT Quant questions and running.

Manager
Manager
User avatar
Joined: 23 Aug 2011
Posts: 83
Followers: 3

Kudos [?]: 19 [0], given: 13

Re: If square roots of numbers are positive.. Is a<c? [#permalink] New post 27 Aug 2012, 17:23
EvaJager wrote:
conty911 wrote:
If square roots of numbers are considered positive and \sqrt{a} + \sqrt{b} = \sqrt{c} + \sqrt{d} + \sqrt{e}, then is a < c?

1.) c = d

2.)\sqrt{b}+\sqrt{d}<\sqrt{e}


Since all the numbers are positive and the square roots are also positive, the question can be restated as is \sqrt{a}<\sqrt{c}?
Also, (1) can be replaced by \sqrt{c}=\sqrt{d}.

(1) Obviously not sufficient. Too many degrees of freedom to choose values for the five variables.

(2) Since \sqrt{b}+\sqrt{d}<\sqrt{e} necessarily \sqrt{b}<\sqrt{e} and then, using the equality in the question stem, we can deduce that \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c}. In conclusion, \sqrt{a}>\sqrt{c}.
Sufficient.

Answer B


Thanks for the reply :), also can you elaborate more on how you deduced this inequality \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c}. I didn't quite understood that :(
_________________

Whatever one does in life is a repetition of what one has done several times in one's life!
If my post was worth it, then i deserve kudos :)

1 KUDOS received
Director
Director
User avatar
Joined: 22 Mar 2011
Posts: 608
WE: Science (Education)
Followers: 43

Kudos [?]: 267 [1] , given: 43

GMAT Tests User
Re: If square roots of numbers are positive.. Is a<c? [#permalink] New post 28 Aug 2012, 05:04
1
This post received
KUDOS
conty911 wrote:
EvaJager wrote:
conty911 wrote:
If square roots of numbers are considered positive and \sqrt{a} + \sqrt{b} = \sqrt{c} + \sqrt{d} + \sqrt{e}, then is a < c?

1.) c = d

2.)\sqrt{b}+\sqrt{d}<\sqrt{e}


Since all the numbers are positive and the square roots are also positive, the question can be restated as is \sqrt{a}<\sqrt{c}?
Also, (1) can be replaced by \sqrt{c}=\sqrt{d}.

(1) Obviously not sufficient. Too many degrees of freedom to choose values for the five variables.

(2) Since \sqrt{b}+\sqrt{d}<\sqrt{e} necessarily \sqrt{b}<\sqrt{e} and then, using the equality in the question stem, we can deduce that \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c}. In conclusion, \sqrt{a}>\sqrt{c}.
Sufficient.

Answer B


Thanks for the reply :), also can you elaborate more on how you deduced this inequality \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c}. I didn't quite understood that :(



(2) Since \sqrt{b}+\sqrt{d}<\sqrt{e} necessarily \sqrt{b}<\sqrt{e} if the sum of two positive numbers is less than another positive number, then each term of the sum is less than that number and then, using the equality in the question stem, we can deduce that \sqrt{a}>\sqrt{c}+\sqrt{d}>\sqrt{c} - if \sqrt{a}\leq\sqrt{c}+\sqrt{d} then the equality in the stem would not hold; if 2 < 3 and 4 < 7, 2 + 4 cannot be equal to 3 + 7. In addition, \sqrt{c}+\sqrt{d}>\sqrt{c} because \sqrt{d} is positive.
In conclusion, \sqrt{a}>\sqrt{c}.

Answer B.
_________________

PhD in Applied Mathematics
Love GMAT Quant questions and running.

Re: If square roots of numbers are positive.. Is a<c?   [#permalink] 28 Aug 2012, 05:04
    Similar topics Author Replies Last post
Similar
Topics:
 New posts The number q is a positive integer. Is the square root of q kevincan 5 09 Jul 2006, 04:21
New posts 1 If x is a positive number and 1/2 the square root of x is bmwhype2 2 09 Jun 2007, 16:33
Popular new posts 2 EXPERTS_POSTS_IN_THIS_TOPIC Numbers-Squares root virtualanimosity 13 04 Nov 2009, 00:22
Popular new posts 1 EXPERTS_POSTS_IN_THIS_TOPIC Square Root = Always Positive? ebonn101 11 23 May 2011, 15:34
New posts 2 Positive square root metallicafan 2 28 Nov 2011, 10:31
Display posts from previous: Sort by

If square roots of numbers are positive.. Is a<c?

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: Bunuel, VeritasPrepKarishma, IanStewart

Search for:


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com