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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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01 Sep 2014, 13:50

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Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?

Sure, look below:

Given: T = 5/9 * (K - 32) ----> Multiply both sides by 9/5, we get ----> 9/5T = (5/9 * 9/5) * (K-32)

----> 9/5 * T = 1 * (K-32) ----> (9/5 )T = K -32 (as x*1 = x) ----> Now add 32 to both sides (to transfer 32 from K-32 towards T), we get ----> (9/5)T + 32 = K

Now susbtitute T = 290 in the last equation, we get

Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 09:18

Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 09:52

Honestly, it is something that you should be looking at most of the time. This is a thinking exam, not at math exam.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 10:46

True, but if you do attempt to answer a question without doing math then there's a higher risk of getting muddled or making careless errors. There's obviously a balancing act and it'd be preferable to have some sort of guidelines to apply in choosing how to tackle a problem

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