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If T = 5/9 * (K - 32), and if T = 290, then K =

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If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 07 Dec 2012, 05:48
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If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5
[Reveal] Spoiler: OA
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 07 Dec 2012, 05:50
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Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


Given that \(290=\frac{5}{9} * (K - 32)\) --> \(290*\frac{9}{5}=K - 32\) --> \(522=K-32\) --> \(K=554\).

Answer: D.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 06 Aug 2013, 22:55
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290=\frac{5}{9}(K-32)
58*9=k-31
i rounded 9 to 10 so
580-58+31=k
then i choose d, no point in doing calculations to waste time
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 01 Sep 2014, 13:50
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 03 Sep 2014, 01:30
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\(290 = \frac{5}{9} * (k-32)\)

\(k = 290*\frac{9}{5} + 32\)

k = 58*9 + 32

Answer would be ending with 4; only option D = 554 fits in

Answer = D
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 03:06
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 03:14
jackrim1 wrote:
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?


Sure, look below:

Given: T = 5/9 * (K - 32) ----> Multiply both sides by 9/5, we get ----> 9/5T = (5/9 * 9/5) * (K-32)

----> 9/5 * T = 1 * (K-32) ----> (9/5 )T = K -32 (as x*1 = x) ----> Now add 32 to both sides (to transfer 32 from K-32 towards T), we get ----> (9/5)T + 32 = K

Now susbtitute T = 290 in the last equation, we get

(9/5) * 290 + 32 = K ----> K = 9 *58 + 32 = 522 + 32 = 544.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 04:28
Ah they multiplied by the reciprocal, I misunderstood that.

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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 05:59
Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5


\(290 * 9 = 5 * (K - 32)\)
\(K = \frac{(290*9) + 32}{5}\)
\(K = 554.\) Ans (D).
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 09:18
Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 09:48
Very good point. What's your strategy upon seeing a question such as that and deciding which tactic to use?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 09:52
Honestly, it is something that you should be looking at most of the time. This is a thinking exam, not at math exam.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink] New post 14 Jul 2015, 10:46
True, but if you do attempt to answer a question without doing math then there's a higher risk of getting muddled or making careless errors. There's obviously a balancing act and it'd be preferable to have some sort of guidelines to apply in choosing how to tackle a problem
Re: If T = 5/9 * (K - 32), and if T = 290, then K =   [#permalink] 14 Jul 2015, 10:46
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