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Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

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Re: If (t- 8) is a factor of t^2 - kt - 48, then k= [#permalink]
24 Jan 2014, 04:55

Factoring the expression: (t - 8) (t - ?), since (t - 8) is a factor, the other bracket has to be (t + 6). The net result is -2. So (B)? Not sure of the answer because I got lost with the signs a bit.

If (t- 8) is a factor of t^2 - kt - 48, then k= [#permalink]
24 Jan 2014, 23:46

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This post received KUDOS

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If (t- 8) is a factor of \(t^2 - kt - 48\), then k=

(A) - 6 (8) - 2 (C) 2 (0) 6 (E) 14

It is given that \((t - 8)\) is a factor of the quadratic expression \(t^2 - kt - 48\) Hence, we need to find the other factor of \(-48\) such that the sum of factors is\(-(\frac{-k}{1})=k\).

Thus, \((8) * x = -48\)

Or, \(x = -6\)

So, \(k = 8 + (- 6) = 2\)

Answer: (C)

Last edited by arunspanda on 01 Nov 2014, 02:02, edited 1 time in total.

Re: If (t- 8) is a factor of t^2 - kt - 48, then k= [#permalink]
22 May 2014, 23:38

Vieta's formulas applied to quadratic: x1+x2= -b/a & x1*x2=c/a From what is given in the question: 8+x2=k and 8*x2=-48 so, x2=-6 and thus 8-6=k i.e. k=2 _________________

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Re: If (t- 8) is a factor of t^2 - kt - 48, then k= [#permalink]
30 Jun 2015, 15:40

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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