Find all School-related info fast with the new School-Specific MBA Forum

It is currently 25 May 2013, 11:00
Customize  |  Hide

If the 4 x 4 grid in the attached picture is filled with the

  Question banks Downloads My Bookmarks Reviews  
Author Message
TAGS:
Director
Director
Status: Preparing for the 4th time -:(
Joined: 25 Jun 2011
Posts: 558
Location: United Kingdom
Concentration: International Business, Strategy
GMAT Date: 06-22-2012
GPA: 2.9
WE: Information Technology (Consulting)
Followers: 8

Kudos [?]: 63 [0], given: 212

GMAT Tests User
If the 4 x 4 grid in the attached picture is filled with the [#permalink] New post 31 Jan 2012, 19:25
00:00

Question Stats:

0% (00:00) correct 100% (26:59) wrong based on 0 sessions
If the 4 x 4 grid in the attached picture is filled with the consecutive integers from 37 to 52, inclusive, so that every row, column and major diagonal sums to the same value, which of the following is a possible value of the sum of the four center cells of the grid (indicated by the shaded area)?

(A) 124
(B) 153
(C) 178
(D) 192
(E) 214

Any idea how to approach this question please?
Attachments

Centre Cells of the grid.xls [20 KiB]
Downloaded 28 times

To download please login or register as a user


_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610 :-(

Director
Director
Status:
Joined: 24 Jul 2011
Posts: 504
GMAT 1: 780 Q51 V48
GRE 1: 1540 Q800 V740
Followers: 37

Kudos [?]: 163 [0], given: 9

Re: Shaded part of the grid [#permalink] New post 01 Feb 2012, 03:58
Sum of the numbers from 37 to 52 = (n/2)[2a + (n-1)d] = (16/2) [74+15] = 8 * 89 = 712

Therefore the sum of all numbers in the grid = 712
If x is the sum of all numbers in a row/column/major diagonal, then
4x = 712
=> x = 178 = sum of all numbers in any row = sum of all numbers in any diagonal = sum of all numbers in either major diagonal

Now, consider the grid as follows:
1' 2' 3' 4'
5' 6' 7' 8'
9' 10' 11' 12'
13' 14' 15' 16'

We know that 1' + 6' + 11' + 16' = 178
4' + 7' + 10' + 13' = 178
=> 1' + 6' + 11' + 16' + 4' + 7' + 10' + 13' = 356
=> 6' + 7' + 10' + 11' + 1' + 13' + 4' + 16' = 356

Also 5' + 6' + 7' + 8' + 9' + 10' + 11' + 12' = 356
and 1' + 5' + 9' + 13' + 4' + 8' + 12' + 16' = 356
=> 6' + 7' + 10' + 11' - 1' - 13' - 4' - 16' = 0

Therefore 6' + 7' + 10' + 11' = 356/2 = 178 = sum of the middle four numbers

Option (C).
_________________

Free profile evaluation by top b-school alumni: email us at info@gyanone.com
B-school application service http://www.gyanone.com/appone.html
[b]Visit our blog: www.gyanone.com/blog

Re: Shaded part of the grid   [#permalink] 01 Feb 2012, 03:58
    Similar topics Author Replies Last post
Similar
Topics:
New posts If there are 4 pictures of different sizes, in how many ways hallelujah1234 4 16 May 2004, 11:46
New posts In the square (in picture) 12w=3x=4y. What fractional part vivek123 2 19 Mar 2006, 07:10
New posts 1 A breaker filled with liquid holds enough to exactly fill 4 blog 3 03 Feb 2008, 00:47
New posts 1 In PQS attached, if PQ =3 and PS = 4, then PR=? (A) 9/4 prasannar 5 26 Jun 2008, 21:39
New posts 1 In the square shown in the attached diagram , 12w = 3x = 4y. amitdgr 2 08 Oct 2008, 06:58
Display posts from previous: Sort by

If the 4 x 4 grid in the attached picture is filled with the

  Question banks Downloads My Bookmarks Reviews  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.