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If the area of a square equals the area of a circle, which of the foll

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If the area of a square equals the area of a circle, which of the foll [#permalink]

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11 May 2009, 14:24
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If the area of a square equals the area of a circle, which of the following is closest to the ratio of the diagonal of the square to the diameter of the circle?

A. 0.95
B. 1.26
C. 1.40
D. 1.57
E. 2.51

M19-21
[Reveal] Spoiler: OA

Last edited by Bunuel on 02 Oct 2014, 02:46, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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11 May 2009, 17:43
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The area of a square equals that of a circle. Which of the following is closest to the ratio of the diagonal of the square to the diameter of the circle?

0.95
1.26
1.40
1.57
2.51

I feel like I'm making a simple mistake somewhere, but can't figure out where.

s^2 = pir^2
s = r sqrt(pi)

diagnal, ds = s (sqrt 2)
diameter, dc = 2r

ds/dc = s (sqrt 2)/2r
ds/dc = r sqrt(pi) (sqrt 2)/2r
ds/dc = sqrt(pi/2)
ds/dc = sqrt(3.14/2)
ds/dc = sqrt(1.57)
ds/dc = 1.26 approx..
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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13 May 2009, 21:32
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say the area of the square and the circle =100

circle:
100=pir^2
r^2~ 33
r~5.7 (closer to 6 than 5)
diameter ~11.4

square
100=s^2
s=10
diagonal = 10sqrt2= ~1.4(10)= 14

ratio square to circle = 14/11.4 ~ 14/11 = 1.27
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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14 May 2009, 01:08
Area of square = Area of Circle

=> (Diagnonal ^2 / 2) = Pi * Diameter^2/4
=> Diagonal/Diameter= SQRT (Pi/4)
=> Diagonal/Diameter = SQRT (1.57)
=> Diagonal/Diameter= ~1.26
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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14 May 2009, 02:51
GMAT TIGER wrote:
The area of a square equals that of a circle. Which of the following is closest to the ratio of the diagonal of the square to the diameter of the circle?

0.95
1.26
1.40
1.57
2.51

I feel like I'm making a simple mistake somewhere, but can't figure out where.

s^2 = pir^2
s = r sqrt(pi)

diagnal, ds = s (sqrt 2)
diameter, dc = 2r

ds/dc = s (sqrt 2)/2r
ds/dc = r sqrt(pi) (sqrt 2)/2r
ds/dc = sqrt(pi/2)
ds/dc = sqrt(3.14/2)
ds/dc = sqrt(1.57)
ds/dc = 1.26 approx..

Agree...good explanation.
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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14 May 2009, 06:52
Good explanations. OA is B.
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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08 Jul 2011, 09:10
what am I doing wrong ?

area of sq = d^2/2
area of circle = pi r^2

equating we get d/r = under root(pi/2) , which is the answer

but we need d/2r so i am getting an additional 1/2 ???
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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01 Oct 2014, 23:29
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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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02 Oct 2014, 02:46
If the area of a square equals the area of a circle, which of the following is closest to the ratio of the diagonal of the square to the diameter of the circle?

A. 0.95
B. 1.26
C. 1.40
D. 1.57
E. 2.51

M19-21

If $$x$$ is the side of the square, then the area of the square is $$x^2$$ and the diagonal of the square is $$x\sqrt{2}$$. If $$d$$ is the diameter of the circle then the area of the circle is $$\pi(\frac{d}{2})^2$$. Because $$x^2 = \pi(\frac{d}{2})^2$$, $$d = \frac{2x}{\sqrt{\pi}}$$. The required ratio $$=\frac{x\sqrt{2}}{\frac{2x}{\sqrt{\pi}}} = \frac{\sqrt{\pi}}{\sqrt{2}} = \sqrt{\frac{\pi}{2}}$$ or approximately $$\sqrt{1.57}$$. This is slightly smaller than $$\sqrt{1.69} = 1.3$$. The best answer is therefore B.

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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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07 Dec 2015, 06:58
Hello from the GMAT Club BumpBot!

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Re: If the area of a square equals the area of a circle, which of the foll [#permalink]

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14 Jan 2017, 03:43
Hello from the GMAT Club BumpBot!

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Re: If the area of a square equals the area of a circle, which of the foll   [#permalink] 14 Jan 2017, 03:43
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