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If the area of an equilateral triangle is x square meters [#permalink]
29 Dec 2010, 18:25
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33% (02:31) wrong based on 0 sessions
If the area of an equilateral triangle is x square meters and the perimeter is x meters, then what is the length of one side of the triangle in meters? A 6 B 8 C 4√2 D 2√3 E 4√3
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Re: Equilateral Triangle Question [#permalink]
29 Dec 2010, 20:49
m990540 wrote: Keep coming up with the wrong answer for this one! Any help would be greatly appreciated.
If the area of an equilateral triangle is x square meters and the perimeter is x meters, then what is the length of one side of the triangle in meters?
A 6 B 8 C 4√2 D 2√3 E 4√3 Let me try Area of Equilateral triangle = perimeter \sqrt{3/4}* S^2 = 3S Simplifying the above equation would give E
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Re: Equilateral Triangle Question [#permalink]
29 Dec 2010, 21:48
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m990540 wrote: Keep coming up with the wrong answer for this one! Any help would be greatly appreciated.
If the area of an equilateral triangle is x square meters and the perimeter is x meters, then what is the length of one side of the triangle in meters?
A 6 B 8 C 4√2 D 2√3 E 4√3 If perimeter of equilateral triangle is x, its side must be x/3. If side is x/3, its area must be (\sqrt{3}/4)*(x/3)^2[Area of equilateral triangle of side 'a' is (\sqrt{3}/4)*a^2] Area of triangle = x = (\sqrt{3}/4)*(x/3)^23*(4/\sqrt{3}) = x/3 (4\sqrt{3}) = x/3 = side of the triangle
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Re: Equilateral Triangle Question [#permalink]
28 Dec 2011, 05:10
Hi, Can anyone simply ; (S^2*Square3)/4=3S (area of equilateral=perimeter) i can not get the correct answer.......
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Re: Equilateral Triangle Question [#permalink]
31 Dec 2011, 06:26
is there any other way solving the problem without using the area-formula for equilateral triangle?
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Re: Equilateral Triangle Question [#permalink]
01 Jan 2012, 01:43
i think we cannot solve it without formula and if we know formula it will hardly take a minute to crack it........ appreciated if some one help us to solve it without formula.
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Re: Equilateral Triangle Question [#permalink]
01 Jan 2012, 03:22
BDSunDevil wrote: is there any other way solving the problem without using the area-formula for equilateral triangle? If you don't know the equilateral triangle area formula, you will need to use the area formula for any triangle i.e. (1/2)*base*altitude You will get the area for the equilateral triangle. Since perimeter = x meters, length of side = x/3 meters. So base = x/3 What about the altitude? You need to use pythagorean theorem to figure it out. The altitude bisects the opposite side in an equilateral triangle so (x/3)^2 = (x/6)^2 + altitude^2 altitude = x/(2\sqrt{3})Area of triangle = (1/2)*(x/3)*(x/(2\sqrt{3}) = x^2/12*\sqrt{3}This is the same as the formula (obviously!) \sqrt{3}/4 * (x/3)^2 = x^2/12*\sqrt{3}
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Re: Equilateral Triangle Question [#permalink]
02 Jan 2012, 01:04
HI, can anyone explain how to get to the correct answer from here: (S^2*Square3)/4=3S.... I got S=12/square3 thanks!!
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Re: Equilateral Triangle Question [#permalink]
02 Jan 2012, 04:28
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Saurajm wrote: HI, can anyone explain how to get to the correct answer from here: (S^2*Square3)/4=3S.... I got S=12/square3 thanks!! Length of the side = S/3 not S. S is the perimeter of the triangle (actually it is given as x in the original question) So area = ((S/3)^2*\sqrt{3})/4 = SYou get S = 12*\sqrt{3}Length of side = S/3 = 12*\sqrt{3}/3 = 4*\sqrt{3}
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If the area of an equilateral triangle is x square meters [#permalink]
26 Nov 2012, 15:01
sorry to bring this up again, but can someone maybe explain to me how we go from
(3*4)/rt3
to 4*rt3 ?
I got 12/rt3 but I didn't know how to factor anymore then!
Thanks a lot!
Kate
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If the area of an equilateral triangle is x square meters [#permalink]
26 Nov 2012, 16:37
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KateG130290 wrote: sorry to bring this up again, but can someone maybe explain to me how we go from
(3*4)/rt3
to 4*rt3 ?
I got 12/rt3 but I didn't know how to factor anymore then!
Thanks a lot!
Kate (3*4)/rt3 = 12/rt3 = (12*rt3)/(rt3*rt3) = (12*rt3)/3 = 4*rt3 Posted from my mobile device
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If the area of an equilateral triangle is x square meters
[#permalink]
26 Nov 2012, 16:37
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