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# If the area of square S and the area of circle C are equal,

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Director
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If the area of square S and the area of circle C are equal, [#permalink]  29 Nov 2004, 21:01
If the area of square S and the area of circle C are equal, then the ratio of the perimeter of S to the circumference of C is closest to

a. 7/9 b. 9/8 c. 9/8 d. 4/3 e. 2/1

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GMAT Club Legend
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Hey, just want to say that it's good to see you back Titleist. It's been a while buddy.
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Best Regards,

Paul

Director
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Hey Paul! [#permalink]  29 Nov 2004, 21:12
Hi Paul! Thanks for the greetings it's good to be back - had a death in the family, changed careers, and found a girlfriend. Ready to get back to business and take the GMAT in December! I'm reading all these posts of guys who started posting at the time I started who have broken the 700 barrier - it's very encouraging. I'm assuming you're one of them.

Last edited by Titleist on 29 Nov 2004, 21:13, edited 1 time in total.
Intern
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I will go for A, the answer i got is 7/11.
Director
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Sorry not the "right" answer. Don't feel bad - this is one of those weird PR questions.
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9/8?

I get to 2/P^-2 which is approximately 2/1.75 but then stuck with answer choices.
Intern
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you have the same answer in the options b and c, is it 2/3 by any chance.
Director
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Yes! very good. I guess 9/8 as answer choice b and c helped a little. my bad.

Director
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I get E. well i dunno if I am wrong but this is how I have done.

square of the side is s

s^2= pi * r^2
s= (sqrt of Pi) * r

ratio of the perimeters= 4s/2 * pi * r
substituting value of s..
i get 2/sqrt of pi which is equvialent to 2/1.77 so going with E
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1.
S = pi*R^2
C = a^2.
S = C -> a*a = pi*R*R - > a = R*sqrt(pi)
2.
Pc = 2*pi*R and Ps = 4*a
->
Pc/Ps = pi*R/(2*a) = sqrt(pi)/2 ~ .89 ~ 8/9
Director
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isn;t it square: circle and not the otherway around..
Manager
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a....closest ratio I got is 7/11 ..answer would less than this.
Director
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