tarek99 wrote:

well, the OA is C, but I don't know how. This is what i've done so far:

S^2=Pi*r^2 then sqrt both sides to get S in terms of the circle:

s= sqrt(pi)r so this is our side of square. then multiply by 4 to get the perimeter of the square:

Perimeter of square: 4r*sqrt(pi)

therefore, the ratio of the perimeter of square to cirum. of circle should be:

4r*sqrt(pi) / 2r*pi = 2*sqrt(pi)/pi or 2/sqrt(pi), but because we can't leave the sqrt sign in the denominator, we leave it as 2*sqrt(pi)/pi which is no where close to the OA. so can anyone help me out here??? i'd really appreciate it.

I picked numbers and approximated for this one.

Let the side of the square = 3

Then 3*3=pi*r^2

If you solve for r you get 3/(sqrt(pi))

So the ration of perimeter to circum. should be 4s/2*pi*r.

Fill in you values and you get 12/2*pi*(sqrt(pi)).

If you reduce you get 2sqrt(pi)/pi. Just aproximate 3.14 for pi and 1.75 for sqrt(pi) and you get 3.5/3.14 or a little more than one. Ans C