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If the average (arithmetic mean) of 5 positive temperatures

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If the average (arithmetic mean) of 5 positive temperatures [#permalink] New post 14 Oct 2005, 11:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the average (arithmetic mean) of 5 positive temperatures is x degrees Fahrenheit, then the sum of the 3 greatest of these temperatures, in degrees Fahrenheit, could be

A. 6x
B. 4x
C. 5x/3
D. 3x/2
E. 3x/5
VP
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 [#permalink] New post 14 Oct 2005, 12:02
B.

Sum of all 5 temperatues = 5*x

(A) out > 5x
(B) possible

(C) through (E) if we find out sum of "remaining" 2 temperatures. It comes out to be greater than sub of 3 given.
Senior Manager
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 [#permalink] New post 14 Oct 2005, 12:14
Since average is x, the sum is 5x. If we consider the lowest for the first 2 temperatures then is should be 1 & 1. So the greatest sum for the 3 high temperatures is: 5x - 2.

A is impossible

B,C,D & E are possible. However, C,D,E are less than B.

Hence the answer (B).
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 [#permalink] New post 14 Oct 2005, 12:14
just pick numbers

1+2+3+4+5=15/5=3

so x=3, then the sum of 3+4+5=12

so 4X=12...B it is..
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 [#permalink] New post 14 Oct 2005, 12:45
For Max, the sum of 3 readings should be as close to 5x as possible, yet < 5x (as the other two readings are positive.)
From the choices co-efficient 4 is the greatest that is less than 5.

So B
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 [#permalink] New post 14 Oct 2005, 12:53
o is positive. so the if the 2 lowest temperature is 0 degrees, then the the average of 3 highest temperature is 5x/3.

So C is the answer.
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 [#permalink] New post 14 Oct 2005, 13:19
nakib77 wrote:
o is positive. so the if the 2 lowest temperature is 0 degrees, then the the average of 3 highest temperature is 5x/3.

So C is the answer.


o is neither negative nor positive.
  [#permalink] 14 Oct 2005, 13:19
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If the average (arithmetic mean) of 5 positive temperatures

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