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If the average (arithmetic mean0 of 5 different numbers is

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If the average (arithmetic mean0 of 5 different numbers is [#permalink] New post 05 Jul 2008, 10:08
If the average (arithmetic mean0 of 5 different numbers is 12, what is the median of the numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of th 4 numbers other than the median is equal o 45.
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Re: If the average [#permalink] New post 05 Jul 2008, 10:16
each option is alone sufficient to solve.
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Re: If the average [#permalink] New post 05 Jul 2008, 11:30
GMBA85 wrote:
each option is alone sufficient to solve.


can you please explain
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Re: If the average [#permalink] New post 06 Jul 2008, 17:40
TheBigCheese wrote:
GMBA85 wrote:
each option is alone sufficient to solve.


can you please explain


If the average (arithmetic mean0 of 5 different numbers is 12, what is the median of the numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of th 4 numbers other than the median is equal o 45.

arithmetic mean0 of 5 different numbers is 12
=>Sum of 5 numbers = 12*5 = 60
Let M be the median

stat1
M = 1/3 *sum4
=> sum5 = sum4+M
60 = sum4 + sum4/3
Suff..we can calculate M from sum4
stat2
sum4 = 45
M = 60-sum4
Suff

D
Re: If the average   [#permalink] 06 Jul 2008, 17:40
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