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If the average of four positive integers is 30, how many

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Senior Manager
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If the average of four positive integers is 30, how many [#permalink] New post 23 Oct 2010, 18:45
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A
B
C
D
E

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Question Stats:

50% (00:00) correct 50% (02:18) wrong based on 2 sessions
If the average of four positive integers is 30, how many integers of these four are greater than 25 ?

1. One of the integers is 100
2. The median of the four integers is 25

The question is not tough, however, I just want to check if my understanding is wrong or there is a problem with this question.

As far as I know, the two statements in DS can not contradict. They both have to be true. I do not see a scenario that both I and II can be true.

II If median is 25, there are only two possibilties:
X, 25, 25, Y
X, 30, 35, Y

either way, there is no way that Statement I can be satisfied ! If one of the integers is 100, then the sum of the other three has to be 20 :?:
[Reveal] Spoiler: OA

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Re: Clarification - M20#14 [#permalink] New post 23 Oct 2010, 19:37
Agreed

Something is amiss, the two statements cannot both be true

Median=25 means middle two digits acreage at 25. This is impossible if numbers are positive, mean is 30 and one of them is 100

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Senior Manager
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Joined: 06 Jun 2009
Posts: 333
Location: USA
WE 1: Engineering
Followers: 1

Kudos [?]: 54 [0], given: 0

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Re: Clarification - M20#14 [#permalink] New post 23 Oct 2010, 19:54
Exactly ! I think this might need to be corrected.

Plus another question in M20 says 4N. However, it is 4^N.

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Re: Clarification - M20#14   [#permalink] 23 Oct 2010, 19:54
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