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If the diameter of a bicycle, including the tire, is 28

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Manager
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If the diameter of a bicycle, including the tire, is 28 [#permalink]

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New post 15 May 2007, 00:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12inches= 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214

for some reason my answer isn't among the answer choices..hmm
Manager
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Re: revolution problem [#permalink]

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New post 15 May 2007, 00:08
Jamesk486 wrote:
If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12inches= 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214

for some reason my answer isn't among the answer choices..hmm


(B) it is

500 feet = 6,000 inches

=> The # of revolutions made = 6,000/(28 x pi) = 68 (approximately)
Director
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Re: revolution problem [#permalink]

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New post 15 May 2007, 00:29
kirakira wrote:
Jamesk486 wrote:
If the diameter of a bicycle, including the tire, is 28 inches, approximately how many revolutions will the wheel make while the bicycle travels 500 feet along a flat road? (12inches= 1 foot)
A. 18
B. 68
C. 117
D. 136
E. 214

for some reason my answer isn't among the answer choices..hmm


(B) it is

500 feet = 6,000 inches

=> The # of revolutions made = 6,000/(28 x pi) = 68 (approximately)


are you still sure that your answer is not among the one.
Director
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New post 15 May 2007, 00:39
how did you guys figure this out?
Quote:
The # of revolutions made = 6,000/(28 x pi) = 68 (approximately)

is the quoted a formula I should know?
Director
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 [#permalink]

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New post 15 May 2007, 00:46
ggarr wrote:
how did you guys figure this out?
Quote:
The # of revolutions made = 6,000/(28 x pi) = 68 (approximately)

is the quoted a formula I should know?


total distance = 12 x 500
circumference of the wheel = 2 pi r = pi d = 28 pi
so n = 6000/(28 pi) = 68 approx...
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New post 15 May 2007, 00:51
ggarr wrote:
how did you guys figure this out?
Quote:
The # of revolutions made = 6,000/(28 x pi) = 68 (approximately)

is the quoted a formula I should know?


No of Revolutions = Total distance / Distance travelled per revolution

Total distance = 500 * 12 = 6000 inches
Distance travelled per revolution = pi * d = pi * 28 inches

Ans is B
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New post 15 May 2007, 15:23
well ok i converted everything to feet, rather~
  [#permalink] 15 May 2007, 15:23
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If the diameter of a bicycle, including the tire, is 28

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