If the function Q is defined by the formula Q = 5w/(4x(z^2))

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If the function Q is defined by the formula Q = 5w/(4x(z^2)) [#permalink]

04 Jun 2011, 12:33

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If the function Q is defined by the formula Q = 5w/(4x(z^2)) , by what factor will Q be multiplied if w is quadrupled, x is doubled, and z is tripled?

A. 1/9
B. 2/9
C. 4/9
D. 3/9
E. 2/27

[Reveal] Spoiler: OA

Last edited by Bunuel on 11 Dec 2012, 02:00, edited 3 times in total.

Edited the question and added the answer choices with OA

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Re: Direct and inverse proportionality [#permalink]

04 Jun 2011, 19:09

IN the expression Q=5w/4xz^2, substitute the values as mentioned :

So new expression is -> 5 * (4w)/(4 * (2x) * (3z)^2)

= 5 * w/(2x * 9 * z^2)

= (2/9) * 5w/4xz^2

= 2/9 * Q

So Q will be multiplied by the factor 2/9.
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Re: Direct and inverse proportionality [#permalink]

06 Jun 2011, 01:34

According to expression Q= 5w/4xz²
now, w'=4w,
x'=2x
z'=3z
Put these values in a same order, we get
Q'= 5(4w)/4(2x)(3z)²
Q'=5w/18xz²
Q'=2/9*(5w/4xz²)
So, Q'= 2/9(Q),q will be a multiple of factor 2/9.
This is the most effective way to solve such question. 8-)

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Re: Direct and inverse proportionality [#permalink]

11 Jun 2011, 17:32

Q = 5W/(4XZ^2)

Q1 = 5(2W)/(4(2X)9X^2) = 2/9 Q

So the factor is 2/9.

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Re: Direct and inverse proportionality [#permalink]

22 Feb 2012, 23:49

Hi guys,

I am sorry, but i still did not get this part.

Q'=5w/18xz²
to
Q'=2/9*(5w/4xz²)

Would anyone be able please to elaborate on it? I would really appreciate it.

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Re: Direct and inverse proportionality [#permalink]

23 Feb 2012, 00:08

SergeNew wrote:

Hi guys,

I am sorry, but i still did not get this part.

Q'=5w/18xz²
to
Q'=2/9*(5w/4xz²)

Would anyone be able please to elaborate on it? I would really appreciate it.

Serge.

If the function Q is defined by the formula Q = 5w/(4x(z^2)), by what factor will Q be multiplied if w is quadrupled, x is doubled, and z is tripled?
A. 1/9
B. 2/9
C. 4/9
D. 3/9
E. 2/27

Given: Q=\frac{5w}{4x*z^2}.

Now, quadruple w, so make it 4w; double x so make it 2x; triple z and substitute these values instead of x, y, and z in the original equation:

\frac{5(4w)}{4(2x)*(3z)^2}=\frac{4*5w}{4*2x*9*z^2}=\frac{4*5w}{18*(4x*z^2)}=\frac{4}{18}*\frac{5w}{4x*z^2}=\frac{2}{9}*\frac{5w}{4x*z^2}. Thus Q is multiplied by \frac{2}{9}.

Answer: B.

Else plug-in values for x, y, and z. Let x=y=z=1 --> Q=\frac{5w}{4x*z^2}=\frac{5}{4}.

4w=4, 2x=2 and 3z=3 --> \frac{5*4}{4*2*3^2}=\frac{4}{18}*\frac{5}{4}=\frac{2}{9}*\frac{5}{4}. Thus Q is multiplied by \frac{2}{9}.

Answer: B.

Hope it's clear.
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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2)) [#permalink]

10 Dec 2012, 22:16

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Q=\frac{{5w}}{{4xz^2}}

Qmod=\frac{{5(4w)}}{{4(2x)(3z)^2}}
Qmod=\frac{{20w)}}{{72xz^2}}
Qmod=\frac{4}{18}*\frac{{5w}}{{4xz^2}}
Qmod=\frac{4}{18}*Q
Qmod=\frac{2}{9}*Q

Answer: 2/9

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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2)) [#permalink]

20 Dec 2012, 15:20

Isn't the tag wrong. It doesnt seem like a 700-level question
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Re: If the function Q is defined by the formula Q = 5w/(4x(z^2)) [#permalink] 20 Dec 2012, 15:20

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If the function Q is defined by the formula Q = 5w/(4x(z^2))

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If the function Q is defined by the formula Q = 5w/(4x(z^2))

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