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Re: Number Prop DS [#permalink]
21 Mar 2011, 21:10

Product of M & N= LCM *GCD ==>56*840 ==>7^2*2^6*5*3

Stmt 1 m could be 7*2^3*5 or 7*2^3*3.. Stmt 2 Since GCD is 56 both m and n should have 7 *2^3 n =>7 *2^3 *3*5 (n is divisible by 15 so it should have 3 and 5 as a factor).. Sufficient

Re: Number Prop DS [#permalink]
05 Sep 2011, 11:21

1

This post received KUDOS

Quote:

If the greatest common factor of two integers, m and n, is 56 and the least common multiple is 840, what is the sum of the m and n?

(1) m is not divisible by 15. (2) n is divisible by 15.

prime factors of 56: 7, 2, 2, 2 prime factors of 840: 7, 2, 2, 2, 3, 5

From Statement 1 m = 56*3 or m=56 Insufficient From Statement 2 m=56; n=840 sufficient

Answer: B _________________

"The best day of your life is the one on which you decide your life is your own. No apologies or excuses. No one to lean on, rely on, or blame. The gift is yours - it is an amazing journey - and you alone are responsible for the quality of it. This is the day your life really begins." - Bob Moawab

Re: If the greatest common factor of two integers, m and n, is [#permalink]
15 Oct 2013, 16:27

It is given GCF = 56 = 7 x 2 x 2 x 2 and LCM = 840 = 56 (GCF) x 15 For more fundamental elaboration:- GCF and LCM ---------- 7 |m , n 2 |m1, n1 2 |m2, n2 2 |m3, n3 --- 1 , 15 or --- 3 , 5 From Statement 1 informs "m" is not divisible by 15, so in above illustration, we can have either 1 or 3 under "m", which makes the statement insufficient to identify the value of m,

From Statement 2 informs "n" is divisible by 15, so in above graphic illustration, we can establish that we will have 1 under "m" and 15 under "n", which is sufficient to derive both the value of n and m

The value of m = 1 x 2 x 2 x 2 x 7 = 56 The value of n = 15 x 2 x 2 x 2 x 7 = 840 m + n = 896

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