If the integer a and n are greater than 1 and the product of the first 8 positive intergers is a multiple of a^n, what is the value of a?
It should be B. With n=6, you can find no integer (except a=2) so that a^6 becomes factor of 8!
... Perhaps i'm confused by the wording of this question.
When I read "the product of the first 8 positive intergers is a multiple of a^n", it means to me:
a^n = k * 8! where k is an integer.
8! = k * a^n where k is an integer.