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Re: If the least common multiple of a positive integer [#permalink]
13 Jun 2008, 05:37

1

This post received KUDOS

Expert's post

D

fist way:

LCM=120=3*2^3*5

1. LCM contains prime number 5, so m or n or both also contain 5. 2. if m:n=3:4 then only both m and m contain 5. Therefore, GCD is 5 or 10. 3. LCM contains 2^3, but in ratio m:n we have only 4=2^2. So, both m and m contain 2. GCD=10.

second way:

m*n=LCM*GCD - it is a formula. m*n=3x*4x=120*GCD ---> GCD=x^2/10 ---> only 10 works. _________________

Re: If the least common multiple of a positive integer [#permalink]
13 Jun 2008, 05:45

walker wrote:

D

fist way:

LCM=120=3*2^3*5

1. LCM contains prime number 5, so m or n or both also contain 5. 2. if m:n=3:4 then only both m and m contain 5. Therefore, GCD is 5 or 10. 3. LCM contains 2^3, but in ratio m:n we have only 4=2^2. So, both m and m contain 2. GCD=10.

I like this. Thanks !

walker wrote:

second way:

m*n=LCM*GCD - it is a formula. m*n=3x*4x=120*GCD ---> GCD=x^2/10 ---> only 10 works.

Thanks for the refresh on the formula, I did not remember.

Re: If the least common multiple of a positive integer m and n [#permalink]
20 Oct 2013, 15:04

1

This post received KUDOS

vd wrote:

If the least common multiple of a positive integer m and n is 120 and m:n is 3:4 what is the greatest common factor of m and n

3 5 6 10 12

Please provide detailed explanations on how to solve this

many thanks

I just plugged in numbers for m & n. If the ratio is 3:4, then using 3 & 4 for their values works fine, since we're trying to find the GCF, and not the actual values of m&n,

so

m*n=LCM*GCF

3*4=120*GCF 12=120*GCF 10=GCF

D.

gmatclubot

Re: If the least common multiple of a positive integer m and n
[#permalink]
20 Oct 2013, 15:04

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