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If the length of Wanda's telephone call was rounded up to

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If the length of Wanda's telephone call was rounded up to [#permalink] New post 14 Jun 2012, 02:09
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If the length of Wanda's telephone call was rounded up to the nearest whole minute by her telephone company, then Wanda was charged for how many minutes for her telephone call?

(1) The total charge for Wanda's telephone call was $6.50.

(2) Wanda was charged $0.50 more for the first minute of the telephone call than for each minute after the first.

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Difficulty: 650
[Reveal] Spoiler: OA

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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 14 Jun 2012, 02:10
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If the length of Wanda's telephone call was rounded up to the nearest whole minute by her telephone company, then Wanda was charged for how many minutes for her telephone call?

(1) The total charge for Wanda's telephone call was $6.50. Clearly insufficient since we don't know the cost per minute of call.

(2) Wanda was charged $0.50 more for the first minute of the telephone call than for each minute after the first. So, if the first minute costs $(x+0.5) then each succeeding minute costs $x. Still not sufficient.

(1)+(2) We have that (x+0.5)+x(n-1)=6.5 --> xn=6, where n is the number of minutes. We have one equation and two unknowns, hence we cannot solve for n. Not sufficient.

Answer: E.
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 14 Jun 2012, 04:27
Hi,

Difficulty level: 600

To find the time duration of Wanda's call,

Using (1),
Total charge for the call = $6.5, we neither know the number of minutes nor call charges. Insufficient.

Using (2),
Wanda was charged $0.50 more for the first minute of the telephone call than for each minute after the first.
x+0.5 for first minute,
for second minute x, & so on,
for the whole call total charges would be nx+0.5 (n = number of minutes)
or nx+0.5 = 6.5
or nx = 6 (1*6 or 6*1 or 2*3 or 3*2)
thus, (n,x) = (1,6) or (6,1) or ....
which means, for 1 min $6 can be charged.
or for 6 mins $1 can be charged. Insufficient.

Answer is (E),

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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 15 Jun 2012, 12:03
clearly ans is E.

well explained above.

OA please?
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 16 Jun 2012, 03:40
Difficulty level: 650

We have to find the duration of the call say N minutes.

1. Statement 1: It gives information about the cost of total call however we do not know per minute cost hence can not calculate the minutes.

2. Statement 2: We know that the cost of first minute was higher by 0.50 cents however we do not know the cost of subsequent minutes. Secondly, we cant calculate the duration of the call with this information.

Put together, we know the total cost and also know that cost of first minute was higher by 0.50. If for example cost of subsequent minutes were 50 cents, the total duration would have been 12 minutes. Reduce the cost of call made after first minute, the duration will change.

Hence answer is E
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 17 Jun 2012, 07:28
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IMO also E is the correct answer. Agree with Manjeet's sol
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 17 Jun 2012, 07:49
Answer E.

The question probably might be D if it had asked the maximum or minimum number of calls she made.
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 22 Jun 2012, 02:56
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SOLUTION

If the length of Wanda's telephone call was rounded up to the nearest whole minute by her telephone company, then Wanda was charged for how many minutes for her telephone call?

(1) The total charge for Wanda's telephone call was $6.50. Clearly insufficient since we don't know the cost per minute of call.

(2) Wanda was charged $0.50 more for the first minute of the telephone call than for each minute after the first. So, if the first minute costs $(x+0.5) then each succeeding minute costs $x. Still not sufficient.

(1)+(2) We have that (x+0.5)+x(n-1)=6.5 --> xn=6, where n is the number of minutes. We have one equation and two unknowns, hence we cannot solve for n. Not sufficient.

Answer: E.
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NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 23 Jul 2012, 06:29
Total call minutes=Total call cost/Cost per min
(i) m=6.5/c insufficient
(ii)m={(c+0.5)+c*(m-1)}/c insufficient
combining;
m can't be calculated
so, (E)
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 20 Aug 2013, 02:50
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Re: If the length of Wanda's telephone call was rounded up to [#permalink] New post 20 Aug 2013, 02:51
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Re: If the length of Wanda's telephone call was rounded up to   [#permalink] 20 Aug 2013, 02:51
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