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Intern
Joined: 26 Mar 2006
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If the number 58 is 1 std dev below the mean & the [#permalink]
 17 Apr 2006, 23:39
If the number 58 is 1 std dev below the mean & the number 98 is 2 std dev above the mean, then what is the mean value?
a. 70
b 72
c 74
d 78
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VP
Joined: 29 Apr 2003
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m - 2d = 58 [m= mean, d=standard dev]
m + 3d = 98
Solving for m, we get 74
Hence C
Its qte easy if the theory behind SD is known!
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Director
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discussed recently ))
_________________
IE IMBA 2010
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VP
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Yep. I posted there also!! :p
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Manager
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how were you able to set up the equations -2dand +3d
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VP
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This is the original problem that I answered!
http://www.gmatclub.com/phpbb/viewtopic ... highlight=
U are rite... it shud be
m -1d =58
m+2d = 98
but then u do not get the value of m as one of the given nos. So I think the above link has the correct version of the question!
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