If the number of fatalities from road accidents declined : GMAT Problem Solving (PS)
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# If the number of fatalities from road accidents declined

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Manager
Joined: 25 Jun 2012
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31 Oct 2012, 21:42
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Difficulty:

15% (low)

Question Stats:

82% (02:00) correct 18% (01:58) wrong based on 45 sessions

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If the number of fatalities from road accidents declined from 9,680 in 1988 to 9,600 in 1989 and then declined a further 20% from 1989 to 1990, what was the approximate percentage decline in the number of fatalities from 1988 to 1990?

(A) 12
(B) 16
(C) 21
(D) 37
(E) 43
[Reveal] Spoiler: OA
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01 Nov 2012, 05:04
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If the number of fatalities from road accidents declined from 9,680 in 1988 to 9,600 in 1989 and then declined a further 20% from 1989 to 1990, what was the approximate percentage decline in the number of fatalities from 1988 to 1990?

(A) 12
(B) 16
(C) 21
(D) 37
(E) 43

Actually we don't need calculate much to answer the question.

We have decline from 9,680 to 9,600 (by 80 points) and then by 20%. Now, since 80 is less than 1% of 9,680, thus the overall decline would be slightly more than 20%. Only answer choice C fits.

P.S. General formula for percent increase or decrease, or percent change:

$$Percent=\frac{Change}{Original}*100$$
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31 Oct 2012, 22:59
If the number of fatalities from road accidents declined from 9,680 in 1988 to 9,600 in 1989 and then declined a further 20% from 1989 to 1990, what was the approximate percentage decline in the number of fatalities from 1988 to 1990?

(A) 12
(B) 16
(C) 21
(D) 37
(E) 43

.8*9600 = 7680

Percentage decline = $$\frac{9680-7680}{9680}*100$$ = $$\frac{2000}{9680}*100$$

We can see that this is slightly higher than $$\frac{2000}{10000}*100$$ ie. slightly higher than 20%

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02 Nov 2012, 11:45
Bunuel wrote:
Actually we don't need calculate much to answer the question.

We have decline from 9,680 to 9,600 (by 80 points) and then by 20%. Now, since 80 is less than 1% of 9,680, thus the overall decline would be slightly more than 20%. Only answer choice C fits.

P.S. General formula for percent increase or decrease, or percent change:

$$Percent=\frac{Change}{Original}*100$$

Again and again Bunuel rejoice my eyes with those eliminations.
What looks so huge as to be done in 20 sec and becomes as easy so that even I can clap it.
Re: If the number of fatalities from road accidents declined   [#permalink] 02 Nov 2012, 11:45
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