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If the operation @ is defined for all a and b by the equatio

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If the operation @ is defined for all a and b by the equatio [#permalink] New post 18 Sep 2003, 06:58
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (01:40) correct 24% (01:00) wrong based on 33 sessions
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4
[Reveal] Spoiler: OA

Last edited by Bunuel on 11 Aug 2014, 23:58, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 21 Sep 2003, 10:37
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Formula: a@b=((a^2)*b)/3
Question: 2@(3@-1)= ?

work within the parenthesis first so solve (3@-1) first


(3@-1)= ((3^2)*-1)/3 = (9*-1)/3= -9/3=-3
now take -3 plug back into equation and solve the rest

2@(-3)=((2^2)*-3)/3 = (4*-3)/3= -12/3= -4

so -4 is the answer....this question is merely testing order of operations

remember PEMDAS
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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 05 Aug 2014, 04:18
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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 00:03
Expert's post
pete300 wrote:
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4


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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 00:09
pete300 wrote:
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4


Hi Bunuel,

Kindly write this equation in mathematical format. It's impossible to understand otherwise :)

Thanks
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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 01:29
Expert's post
PareshGmat wrote:
pete300 wrote:
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4


Hi Bunuel,

Kindly write this equation in mathematical format. It's impossible to understand otherwise :)

Thanks


There is nothing wrong with the format.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 02:05
Bunuel wrote:
PareshGmat wrote:
pete300 wrote:
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4


Hi Bunuel,

Kindly write this equation in mathematical format. It's impossible to understand otherwise :)

Thanks


There is nothing wrong with the format.


a@b =(a^2*b)/3

Is it \frac{a^{2b}}{3} or

\frac{ba^2}{3} ??
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Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 02:12
Expert's post
PareshGmat wrote:
Bunuel wrote:
PareshGmat wrote:
If the operation @ is defined for all a and b by the equation a@b =(a^2*b)/3, then 2@(3@-1) =

A. 4
B. 2
C. -4/3
D. -2
E. -4

Hi Bunuel,

Kindly write this equation in mathematical format. It's impossible to understand otherwise :)

Thanks


There is nothing wrong with the format.


a@b =(a^2*b)/3

Is it \frac{a^{2b}}{3} or

\frac{ba^2}{3} ??


If it were \frac{a^{2b}}{3}, then it would be written as (a^(2*b))/3.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Kudos [?]: 201 [0], given: 165

Re: If the operation @ is defined for all a and b by the equatio [#permalink] New post 12 Aug 2014, 02:27
a@b = \frac{ba^2}{3}

2@(3@-1)

Solving the bracket first

3@-1= \frac{-1*3^2}{3} = -3

2@-3= \frac{-3*2^2}{3} = -4

Answer = E
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Re: If the operation @ is defined for all a and b by the equatio   [#permalink] 12 Aug 2014, 02:27
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