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If the operation # is one of the four arithmetic operations

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If the operation # is one of the four arithmetic operations [#permalink] New post 18 Sep 2010, 19:57
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If the operation # is one of the four arithmetic operations addition, subtraction, multiplication and division, is (6#2)#4 = 6#(2#4)

(1) 3#2 > 3

(2) 3#1 = 3

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Re: DS question [#permalink] New post 18 Sep 2010, 20:01
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If the operation # is one of the four arithmetic operations: addition, subtraction, multiplication and division. Is (6#2)#4 = 6#(2#4) ?

(1) 3#2 > 3. # can be either multiplication or addition. In BOTH cases (6#2)#4 = 6#(2#4) is true: (6*2)*4=6*(2*4)=48 and (6+2)+4=6+(2+4)=12. Sufficient.

(2) 3#1 = 3. # can be either multiplication or division. If it's division the the answer to the question is No and if it's multiplication answer to the question is YES. Two different answers. Not sufficient.

Answer: A.
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Re: DS question [#permalink] New post 18 Sep 2010, 20:10
Bunuel wrote:
If the operation # is one of the four arithmetic operations- addition, subtraction, multiplication and division. Is (6#2)#4= 6#(2#4)

(1) 3#2 > 3, # can be either multiplication or addition in BOTH cases (6#2)#4 = 6#(2#4) is true: (6*2)*4=6*(2*4)=48 and (6+2)+4=6+(2+4)=12. Sufficient.

(2) 3#1 = 3, # can be either multiplication or division. If it's division the the answer to the question is No and if it's multiplication answer to the question is YES. Two different answers. Not sufficient.

Answer: A.



Oh!! :( Anyways thanks Bunuel..I just saw two operations and so felt like i cant solve !!Now I gt it..
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Re: DS question [#permalink] New post 19 Sep 2010, 16:56
Same explanation like Bunnel. Dnt worry I used to make more silly mistakes than what you have done now...And it is all these silly mistakes that afect our score in a huge way....So just relax and solve the problems.....
I am understanding that Panic=failure during exams :)
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Re: DS question [#permalink] New post 21 Sep 2010, 10:12
ravitejapandiri wrote:
Attachment:
DS3.PNG
Please explain me this one..I get Answer C because Fact 1 itself is not sufficient to solve the problem.

F1:Gives * OR +
F2:Gives * OR %

So both give * as the appropriate sign.Hence C

Am I going somewhere badly?


You're given that the operation satisfies the associate property. The associative property is true of addition [(6+2) + 4 = 6 + (2+4)] and multiplication [(6*2) * 4 = 6 * (2*4)], but not of subtraction or division. If we can determine whether the operation is multiplication or addition, or if it's subtraction or division, then we have enough information.

(1) A quick test of each operation will show you that the triangle is either multiplication or addition. Regardless of which one it is, we know that it will satisfy the associative property. Sufficient.

(2) Again, a quick test will show you that the triangle is either multiplication or division. Since multiplication satisfies the property, but division does not, we can't determine the answer. Insufficient.

(A)
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Re: If the operation # is one of the four arithmetic operations [#permalink] New post 21 Jun 2013, 01:48
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Re: If the operation # is one of the four arithmetic operations [#permalink] New post 22 Jun 2013, 02:20
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ravitejapandiri wrote:
If the operation # is one of the four arithmetic operations addition, subtraction, multiplication and division, is (6#2)#4 = 6#(2#4)

(1) 3#2 > 3

(2) 3#1 = 3

Attachment:
DS3.PNG


We basically need to answer either a YES or a NO for the equation (6#2)#4 = 6#(2#4)
And if we see the equation, then we know for sure that we can answer the question if # is :-

+ or * =>YES, Equation will hold => Sufficient
- or / => NO Equation will not hold => Sufficient

Now, looking at stetements:

(1) 3#2 > 3
# can either be + or * to hold true, which is one of our conditions as listed above, hence Sufficient
(2) 3#1 = 3
# can be either * or /, hence in this case we cannot be sure as it consists of one possibility from each condition that we had laid out earlier, and thus will result in a YES for * and a NO for /.

Thus (2) is not sufficient as we cannot come up with a definite answer.

Hence, A
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Re: If the operation # is one of the four arithmetic operations [#permalink] New post 28 Jan 2014, 00:31
At the risk of sounding stupid, the GMAT Quant thus far has taught me to consider all possible conditions when solving a DS problem and choose only that answer which holds true universally in all cases. Hence my question in this case is:

(1) says the operation can either be Addition (+) or Multiplication (X)

The question asks if LHS = RHS using the above operations in place of the symbol
My observation :
(a) if you use multipication in place of the symbol then LHS = RHS
(b) if you use addition in place of the symbol then LHS = RHS
(c) But if you use a combination of multiplication and addition in the equation then LHS not equal to RHS.

Shouldn't the above (C) be a possibility too, since all we know from (1) is that it can be any operation (+ or X). No where is it specified that the same operation is to be performed on both sides of the equation

Similarly,

(2) says the operation can either be Multiplication (X) or Division (/)

Just as in the above reasoning, if you use a combination, then LHS not equal to RHS

THus using (1) and (2) together, only Multiplication holds good to satisfy both conditions

Therefore shouldn't the answer be (C).

Sorry if this is a stupid question.

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Re: If the operation # is one of the four arithmetic operations [#permalink] New post 28 Jan 2014, 00:37
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sriniash wrote:
At the risk of sounding stupid, the GMAT Quant thus far has taught me to consider all possible conditions when solving a DS problem and choose only that answer which holds true universally in all cases. Hence my question in this case is:

(1) says the operation can either be Addition (+) or Multiplication (X)

The question asks if LHS = RHS using the above operations in place of the symbol
My observation :
(a) if you use multipication in place of the symbol then LHS = RHS
(b) if you use addition in place of the symbol then LHS = RHS
(c) But if you use a combination of multiplication and addition in the equation then LHS not equal to RHS.

Shouldn't the above (C) be a possibility too, since all we know from (1) is that it can be any operation (+ or X). No where is it specified that the same operation is to be performed on both sides of the equation

Similarly,

(2) says the operation can either be Multiplication (X) or Division (/)

Just as in the above reasoning, if you use a combination, then LHS not equal to RHS

THus using (1) and (2) together, only Multiplication holds good to satisfy both conditions

Therefore shouldn't the answer be (C).

Sorry if this is a stupid question.

Experts Please assist....


If the operation # is ONE of the four arithmetic operations: addition, subtraction, multiplication and division. Is (6#2)#4 = 6#(2#4) ?

The above means that # in the expression, (6#2)#4 = 6#(2#4), is addition OR subtraction OR multiplication OR division.

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Hope it helps.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If the operation # is one of the four arithmetic operations   [#permalink] 28 Jan 2014, 00:37
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