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If the price increased by X% from 2001 to 2002 and by [#permalink]
18 Jan 2010, 01:29
Question Stats:
100% (05:45) correct
0% (00:00) wrong based on 0 sessions
Hi, Can anyone help me in solving and throwing some light on the reasoning behind the following question:
Q: If the price increased by X% from 2001 to 2002 and by Y% from 2002 to 2003, what is the percentage increase from 2001 to 2003? 1. XY=30 2. 100X+100Y+XY=800
Thanks in advance -Amit
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Tuck Thread Master
Joined: 20 Aug 2009
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Location: Tbilisi, Georgia
Schools: Stanford (in), Tuck (WL), Wharton (ding), Cornell (in)
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Re: Percentage problem [#permalink]
18 Jan 2010, 05:54
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Price in 2002=(1+x)*Price-in-2001
Price in 2003=(1+y)*Price-in-2002=(1+x)(1+y)*Price-in-2001=(1+x+y+xy)*Price-in-2001
So basically, we need to determine (1+x+y+xy), where x=X/100, y=Y/100. 1+X/100+Y/100+XY/10,000
St1: XY=30 - > Clearly Insufficient
St2: 100X+100Y+XY=800; => X+Y+XY/100 = 8 => X/100+Y/100+XY/10,000 = 0.08 That's what we wanted. Sufficient
(B)
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Manager
Joined: 03 Sep 2009
Posts: 80
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Re: Percentage problem [#permalink]
18 Jan 2010, 09:16
Many thanks for the explanation!!
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Re: Percentage problem
[#permalink]
18 Jan 2010, 09:16
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