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If the price of sugar falls by 75/2 %, a person can buy 33
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14 Oct 2005, 07:00
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If the price of sugar falls by 75/2 %, a person can buy 33 kgs more for $560. If the price had been risen by 75/2 %, how much sugar would he have bought for the same sum ?
a)36
b)40
c)42
d)45
e)46
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 40 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?
A. 1 hour
B. 1 hour 10 minutes
C. 2 hours 30 minutes
D. 1 hour 40 minutes
E. 2 hours 10 minutes
Need smiple explanation pls for the above 2.
thks
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Re: If the price of sugar falls by 75/2 %, a person can buy 33
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14 Oct 2005, 09:00
[quote="sushom101"]If the price of sugar falls by 75/2 %, a person can buy 33 kgs more for $560. If the price had been risen by 75/2 %, how much sugar would he have bought for the same sum ?
a)36
b)40
c)42
d)45
e)46
if x is original price per bag and y is original number of bags he can buy. x * y = 560. After rebate .625 * x * (y+33) = 560. solve for x and y.
Then 560/(1.375*x) is answer.
Re: If the price of sugar falls by 75/2 %, a person can buy 33
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15 Oct 2005, 18:23
sushom101 wrote:
thanks all,
SIMPLE Answers for 1 & 2
can i get a similar ...simpler method for question 1 pls. : :
Ask and you shall receive
Question 1.
discount is 75/2% a fancy way of saying 37.5% = change to simple fraction = 3/8 thus the discount is 5/8 which is 62.5%
with a 37.5% discount you can 33 more kgs for $560
price x volume = $560
write down the equation 5/8P(V+33) = $560
P*V = 560 thus, V = 560/P substitute
5/8P(560/P+33) = 560
350 + (33)5/8P = 560
(33)*5/8P = 210
P = 210 x 8/(3*11*5)
P = (14*8)/11
So what will V be when you increase the Price by 37.5%?
1.375 = 11/8
11/8*P = 11/8 x (14)(8)/11 = 14
Thus 14V=560
V=560/14=40
*remember don't make any unnecessary calculations
Second problem
These rate problems require you to find a common element between the 2 objects. In this particular problem, Time (the time it took to meet) is the common element.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
gmatclubot
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