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More:"All I wish someone had told me about GMAT beforehand" There are many things you want to know before doing the GMAT exam (how is exam day, what to expect, how to think, to do's...), and you have them in this blog, in a simple way

Last edited by Bunuel on 21 Mar 2013, 03:46, edited 1 time in total.

Re: If the product of the integers a, b, c and d is 546 and if 1 [#permalink]
21 Mar 2013, 08:14

1

This post received KUDOS

Alright, so we know that the product of a,b,c and d is 546 and 1<a<b<c<d so the first thing we need to do is to break down 546 into a product of prime factors :

546 divided by 2 yields 273 273 divided by 3 yields 91 91 divided by 7 yields 13

Which means that 546 = 2*3*7*13.

So if we consider a = 2, b = 3, c = 7 and d = 13 (in respect to the second condition : 1<a<b<c<d), we have : b+c = 3 + 7 = 10 which is answer choice D.

"If the product of the integers a, b, c and d is 546 and if 1 < a < b < c < d, what is the value of b+c?"

Factors of 546:

546 | 2 273 | 3 91 | 13 7 | 7 1 | 1

If 1 < a < b < c < d, the only possible way is:

d=13 c=7 b=3 a=2

Therefore: b+c = 3 + 7 = 10

Answer D

Make prime factorization of 546: 546=2*3*7*13.

Now, since given that 1 < a < b < c < d, then a=2, b=3, c=7 and d=13 --> b+c=3+7=10.

Answer: D.

Answer is D

Hi Brunel - Can we actually expect such easy questions to come in GMAT? Just trying to make sure i dont get too excited by solving these quicker! _________________