If the right square has an area that is 800% greater than : PS Archive
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If the right square has an area that is 800% greater than

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If the right square has an area that is 800% greater than [#permalink]

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30 Sep 2006, 13:42
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If the right square has an area that is 800% greater than that of the left square, then the ratio of the length of line segment AC to that of line segment BC is

(A) 3:1 (B) sqrt (10):1 (C) 10:3 (D) 7:2 (E) none of these
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Line Segments.doc [28.5 KiB]

Last edited by kevincan on 30 Sep 2006, 23:06, edited 1 time in total.
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30 Sep 2006, 21:48
Getting 3:sqrt(2), but not in the answers.

Can someone elaborate on this?
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30 Sep 2006, 23:45
X & Y wrote:
Getting 3:sqrt(2), but not in the answers.

Can someone elaborate on this?

If u take side of small square as 1 unit, its area is 1 square unit.

If u take side of large square as 3 units, its area is 9 square units.

This way large square has 800% area greater than smaller one.
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30 Sep 2006, 23:54
800% greater. So if first (left) square has area 100, second (right) has 900.
area ratio 900:100 => 9:1
side ratio 3:1
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01 Oct 2006, 15:21
Was making silly mistake.
Instead of 9:1, I was calculating with 8:1..

Thanks..
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01 Oct 2006, 15:21
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