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# If the sum of the first n positive integers is S , what is

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Director
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If the sum of the first n positive integers is S , what is [#permalink]

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24 Jan 2005, 18:12
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the sum of the first n positive integers is S , what is the sum of the first n positive even integers, in terms of S ?
(A) S/2
(B) S
(C) 2S
(D) 2S + 2
(E) 4S

Last edited by vprabhala on 24 Jan 2005, 18:15, edited 1 time in total.
Director
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24 Jan 2005, 18:14
Answer is A and C = 2S

i know its a typo
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24 Jan 2005, 18:16
rxs0005 wrote:
Answer is A and C = 2S

i know its a typo

the way i approached it is n(n+1)/2 is the sum of first n +ve integers.. is that the way..
Director
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24 Jan 2005, 18:23
for this i just took sample numbers and chekce dthem twice with diff sets

it came 2S

is it right
VP
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24 Jan 2005, 18:33
I am getting "D".....2S+2
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24 Jan 2005, 18:38
If the sum of the first n positive integers is S , what is the sum of the first n positive even integers, in terms of S ?

let n = 5

1+2+3+4+5 = 15 = S

so first n positive intgers = 2 + 4 + 6 + 8 + 10 = 30 = 2S
VP
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24 Jan 2005, 18:41
rxs0005 wrote:
If the sum of the first n positive integers is S , what is the sum of the first n positive even integers, in terms of S ?

let n = 5

1+2+3+4+5 = 15 = S

so first n positive intgers = 2 + 4 + 6 + 8 + 10 = 30 = 2S

....calculation mistake....u r right it is 2S...my bad. ...sum of first n even integers is n(n+1)...and sum of first n integers is n(n+1)/2
Director
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24 Jan 2005, 18:45
no sweat dude it happens just dont do it on the REAL DEAL !!! DAY !!
VP
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24 Jan 2005, 18:51
rxs0005 wrote:
no sweat dude it happens just dont do it on the REAL DEAL !!! DAY !!

Who cares abt real deal day ??
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24 Jan 2005, 20:41
S=1+2+3+4+...
S1=2+4+6+8+...=2(1+2+3+4+...)=2S

A
24 Jan 2005, 20:41
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