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# If the two-digit integers M and N are positive and have the

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If the two-digit integers M and N are positive and have the [#permalink]  20 May 2007, 04:20
If the two-digit integers M and N are positive and have the same digits, but in the reverse order, which CANNOT be the sum of M and N?

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Director
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the sum should be a multiple of 11.
Intern
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You are right:)

Can you detail some of your thinking?

Wendy
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I agree with Grad's explanation. Edited my post.

Last edited by vshaunak@gmail.com on 21 May 2007, 03:27, edited 1 time in total.
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Let digits be a and b

Let M = 10a + b, hence N = 10b + a (reverse order)

M + N = 10a + b + 10b + a => 11(a+b)

Hence choice A
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