If the two-digit number M contains the digits x and y, what is the remainder when M is divided by 6?
(1) M is not odd.
(2) x + y = 12
Given - A 2 digit Number M = XY
where we dont know what are x and y -
St 1) Gives us that XY / YX is Even - Could be 48 , Could be 54 , could be 36, So no single answer can be found out.
St 2) X + Y = 12
Gives - M = 39 / 93 / 48 / 84 / 66 - So no single answer to question "What is remainder when M is divided by 6?" could be found out,
Combining Both - St 1 and St 2
Since M cannot be Odd - Only numbers satisfying St 1 and St 2 both are - 48 / 84 / 66
All of them will give same Remainder ZERO
when divided by 6.
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