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If the two-digit number M contains the digits x and y, what

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If the two-digit number M contains the digits x and y, what [#permalink] New post 21 Sep 2012, 23:59
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If the two-digit number M contains the digits x and y, what is the remainder when M is divided by 6?

(1) M is not odd.

(2) x + y = 12
[Reveal] Spoiler: OA

Last edited by Bunuel on 22 Sep 2012, 03:33, edited 1 time in total.
Renamed the topic.
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Re: DS Tricky [#permalink] New post 22 Sep 2012, 01:42
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rohitgarg wrote:
If the two-digit number M contains the digits x and y, what is the remainder when M is divided by 6?

(1) M is not odd.

(2) x + y = 12


Given - A 2 digit Number M = XY
where we dont know what are x and y -

St 1) Gives us that XY / YX is Even - Could be 48 , Could be 54 , could be 36, So no single answer can be found out.

St 2) X + Y = 12
Gives - M = 39 / 93 / 48 / 84 / 66 - So no single answer to question "What is remainder when M is divided by 6?" could be found out,

Combining Both - St 1 and St 2

Since M cannot be Odd - Only numbers satisfying St 1 and St 2 both are - 48 / 84 / 66

All of them will give same Remainder ZERO when divided by 6.

Hence Answer
[Reveal] Spoiler:
C

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Re: If the two-digit number M contains the digits x and y, what [#permalink] New post 22 Sep 2012, 03:43
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1 gives M is even. NS

2 gives M is divisble by 3. NS

1&2 sufficient. if a number is even and divisible by 3, it will be divisible by 6 as well.
Re: If the two-digit number M contains the digits x and y, what   [#permalink] 22 Sep 2012, 03:43
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