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If the two sets have an equal number of numbers, is the mean

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If the two sets have an equal number of numbers, is the mean [#permalink] New post 29 Apr 2006, 13:00
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If the two sets have an equal number of
numbers, is the mean of set Q lower than the
mean of set P?
(1) Set Q consists of consecutive even integers
and set P of consecutive odd integers.
(2) The median of Q is higher than the mean of P
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 [#permalink] New post 29 Apr 2006, 15:01
mean(P)>mean(Q)

1) P has even consecutive number, Q has odd consecutive number
In sufficient, P can be 2,4,6 and Q can be either 11,13,15 or 1,3,5

2) median (Q) > mean (P)
alone not sufficient

Togather!

if total number is odd
consecurive number median is equal to mean
eg. 1,3,5 =>(median, mean)=(3,3)

even for total number is even
median = mean
eg. 1,3,5,7 =>(4,4)

so median(Q)>mean(P)
and both are consecutive numbers
mean(Q)>mean(P)

sufficient

hence C is the answer
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 [#permalink] New post 29 Apr 2006, 15:50
chiragr wrote:
mean(P)>mean(Q)

1) P has even consecutive number, Q has odd consecutive number
In sufficient, P can be 2,4,6 and Q can be either 11,13,15 or 1,3,5

2) median (Q) > mean (P)
alone not sufficient

Togather!

if total number is odd
consecurive number median is equal to mean
eg. 1,3,5 =>(median, mean)=(3,3)

even for total number is even
median = mean
eg. 1,3,5,7 =>(4,4)

so median(Q)>mean(P)
and both are consecutive numbers
mean(Q)>mean(P)

sufficient

hence C is the answer


I concur. Very good explanation btw.
  [#permalink] 29 Apr 2006, 15:50
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