If there are 400 women at College X and 200 students live : DS Archive
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# If there are 400 women at College X and 200 students live

Author Message
Joined: 31 Dec 1969
Location: Russian Federation
Concentration: Technology, Entrepreneurship
GMAT 1: 710 Q49 V0
GMAT 2: 700 Q V
GMAT 3: 740 Q40 V50
GMAT 4: 700 Q48 V38
GMAT 5: 710 Q45 V41
GMAT 6: 680 Q47 V36
GMAT 7: Q42 V44
GMAT 8: Q42 V44
GMAT 9: 740 Q49 V42
GMAT 10: 740 Q V
GMAT 11: 500 Q47 V33
GMAT 12: 670 Q V
WE: Engineering (Manufacturing)
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Kudos [?]: 202 [0], given: 102297

If there are 400 women at College X and 200 students live [#permalink]

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10 Oct 2004, 14:23
00:00

Difficulty:

(N/A)

Question Stats:

100% (02:13) correct 0% (00:00) wrong based on 0 sessions

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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If there are 400 women at College X and 200 students live off-campus, how many students does College X have?

A: 120 women live off-campus.

B: There are half as many men at College X as there are students who live on-campus.
Manager
Joined: 24 Aug 2004
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10 Oct 2004, 22:15
The question seems slightly ambiguous to me:

When it says " There are 400 Women at College X and 200 students live offcampus" .. does the 'women' imply only female students or possibly, female teachers or other staff inclusive.

If i think in this line, i get the answer as E.

However, if by 'women' the question implies female students, and 'men' imply only male students (not teachers, staff etc): then here is a different solution:

A. 120 women and 80 men students live offcampus. : no data about men living on campus. insufficient

B. can solve the problem : (no of men in college) = 1/2 * (400 + no of men in college)

By this logic: B is sufficent.
VP
Joined: 13 Jun 2004
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Location: London, UK
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10 Oct 2004, 22:28
I agree with Target 780. I mean the question is really not clear. Concerning the potential flaw, I agree about "women" and "students".
Intern
Joined: 29 Jun 2004
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Here's how you work it out... [#permalink]

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11 Oct 2004, 04:18
Here's how you work it out...

Code:
Women               Men             Total

Off Campus                                           200

On Campus                                             x

Total             400                 x/2

400 + x/2 = 200 + x

Here's how you work it out...   [#permalink] 11 Oct 2004, 04:18
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