Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

03 Jan 2008, 14:40

8

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

62% (02:35) correct
38% (01:53) wrong based on 335 sessions

HideShow timer Statistics

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

03 Jan 2008, 23:45

Ravshonbek wrote:

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

04 Jan 2008, 06:07

4

This post received KUDOS

kazakhb wrote:

I can't understand why i can't think the way as you guys do, especially "wisconsin", generally he answers every question in this forum, if i was to solve that problem I would need million years(

Most people feel like this when they first start studying for the GMAT. It's not that the math is extremely difficult, it's how the math is being tested that's strange and new. When I first started out I spent lots of time on this forum and made sure I really understood the concepts and reasoning behind each question. In my opinion it's not enough to blindly memorize formulas for this test, you need to understand WHY a question is solved the way it's solved. This way, when the GMAT throws you for a loop, you have solid math founded in an understanding that allows you to apply it to a broad spectrum of problems...and not just on problems and problem types you've seen in the past.

so keep asking questions and digging deeper on here and before long you'll be a pro! there are also great books out there to help you brush up on math skills. I love the MGMAT series for most quant topics and VeritasProject GMAT for combinatorics. You may want to give them a look as well

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

25 Aug 2008, 09:51

Ravshonbek wrote:

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

Answers: (A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

{1,2,3,4} {4,6,8} b/a not integer 4/3,6/3,8/3 p = 3/12 =1/4
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

27 Sep 2009, 10:06

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

Answers: (A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

Soln: a is from the following set {1,2,3,4} b is from the following set {4,6,8}

Total number of ways of choosing 2 integers, one from each set is = 4* 3 = 12 ways

Now the number of possibilities where b/a is not an integer is for the following outcomes {b,a} => {4,3},{6,4},{8,3} = 3 ways

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

05 Mar 2010, 06:45

x2suresh wrote:

Ravshonbek wrote:

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

Answers: (A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

{1,2,3,4} {4,6,8} b/a not integer 4/3,6/3,8/3 p = 3/12 =1/4

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

29 Feb 2012, 10:44

OK, here's an example of how to get an easy question wrong. I assumed (misread) the question to mean that a and b sets are interchangeable. Implying that a and b could be selected from either {1,2,3,4} or {4,6,8}.

I now realize that I had misread the question, but if that was the original question, then: P(b/a is not an integer) = P(b/a not an integer where b in {1234} and a in {468}) + P(b/a not an integer where b in {468} and a in {1234}) = 11/12 + 3/12 = 7/12.

Going back to the question that was asked: P(b/a not an integer where b in {468} and a in {1234}) = 3/12 = 1/4.

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

02 Sep 2014, 14:41

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

17 Oct 2015, 09:23

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

(A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

In such problems, it is better to first write down all the cases that are in cosideration

Set A = {1, 2, 3, 4} Set B = {4, 6, 8}

Total outcomes: 4*3 = 12

Favourable outcomes: We need B/A, hence considering one element of the set B at a time

4: only 3 satisfies our condition (4 is divisible by 1, 2 and 4) 6: only 4 satisfies our condition (6 is divisible by 1, 2 and 3) 8: only 3 satisfies our condition (8 is divisible by 1, 2 and 4)

Favourable outcomes = 3 Probability = 3/12 = 1/4 Option B
_________________

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

06 Apr 2016, 17:18

Ravshonbek wrote:

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

(A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

a relatively easy question that can be solved by enumerating all the outcomes: 1st list: 1, 2, 3, 4 2nd list: 4, 6, 8

now, possible options: 4/1 4/2 4/3 - non-integer 4/4

6/1 6/2 6/3 6/4 - non-integer

8/1 8/2 8/3 - non-integer 8/4

total 12 outcomes, out of which 3 are "successful" outcomes. 3/12 = 1/4

Re: If two numbers, a and b, are to be chosen from a set of 4 [#permalink]

Show Tags

20 Jul 2016, 03:47

Ravshonbek wrote:

If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 4, respectively, what is the probability that b/a will not be an integer?

(A) 1/6 (B) 1/4 (C) 1/3 (D) 1/2 (E) 2/3

Am I the only one who interpreted the question in the following manner?

Given that the first set consists of 4 consecutive integers starting with 1, I assumed the set will be something like this {10, 11, 12, 13} or {102,103,104,105} and same for the second set {404, 406, 408}. This made me lose my mind on how to go about

gmatclubot

Re: If two numbers, a and b, are to be chosen from a set of 4
[#permalink]
20 Jul 2016, 03:47

Happy New Year everyone! Before I get started on this post, and well, restarted on this blog in general, I wanted to mention something. For the past several months...

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Post-MBA I became very intrigued by how senior leaders navigated their career progression. It was also at this time that I realized I learned nothing about this during my...